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Oksanka [162]
3 years ago
7

???????anyone know...

Mathematics
1 answer:
RUDIKE [14]3 years ago
7 0
The answer is:  " 60° " .
__________________________________________________________
     " m∠A = 60° " .
__________________________________________________________
Explanation:
__________________________________________________________

Note:  All triangles, by definition, have 3 (three) sides and 3 (three angles).

The triangle shown (in the "image attached") has three EQUAL side lengths.   Therefore, the triangle shown is an "equilateral triangle" and has 3 (three) equal angles, as well.

All triangles by, definition, have 3 (three) angles that add up to "180° " .

Since each of the 3 (three) angles is equal;  and the three angles are:  

  "∠A" , "∠B" , and "∠C" ;

We can find the measure of "∠A" ; denoted as:  "m∠A" ; as follows:
______________________________________________________
    m∠A  = 180° ÷ 3 = 60° .
______________________________________________________
The answer is:  " 60° " .
______________________________________________________
   m∠A = " 60° " .
______________________________________________________
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Answer:

a. when x=1 so substitute 1 to any X in the given equation.

y=-3(1)+2.5

y=-3+2.5

y=-0.5

b.when x is -1.5 so substitute -1.5 to any x in the equation

y=-3(-1.5)+2.5

y=-4.5+2.5

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2 years ago
URGENT HELP PLEASE.
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W + 2w = 60

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6 0
3 years ago
Given: (↔AB) ║ (↔CD)
nordsb [41]
1) m = y2 - y1/x2 - x1
y = mx + b
m = 7 - 0/3 - 8
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2 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
2 years ago
What is 874 base 9 multiplied by 676 base 9?​
Gekata [30.6K]

Consider the digit expansion of one of the numbers, say,

676₉ = 600₉ + 70₉ + 6₉

then distribute 874₉ over this sum.

874₉ • 6₉ = (8•6)(7•6)(4•6)₉ = (48)(42)(24)₉

• 48 = 45 + 3 = 5•9¹ + 3•9⁰ = 53₉

• 42 = 36 + 6 = 4•9¹ + 6•9⁰ = 46₉

• 24 = 18 + 6 = 2•9¹ + 6•9⁰ = 26₉

874₉ • 6₉ = 5(3 + 4)(6 + 2)6₉ = 5786₉

874₉ • 70₉ = (8•7)(7•7)(4•7)0₉ = (56)(49)(28)0₉

• 56 = 54 + 2 = 6•9¹ + 2•9⁰ = 62₉

• 49 = 45 + 4 = 5•9¹ + 4•9⁰ = 54₉

• 28 = 27 + 1 = 3•9¹ + 1•9⁰ = 31₉

874₉ • 70₉ = 6(2 + 5)(4 + 3)10₉ = 67710₉

874₉ • 600₉ = (874•6)00₉ = 578600₉

Then

874₉ • 676₉ = 578600₉ + 67710₉ + 5786₉

= 5(7 + 6)(8 + 7 + 5)(6 + 7 + 7)(0 + 1 + 8)(0 + 0 + 6)₉

= 5(13)(20)(20)(1•9)6₉

= 5(13)(20)(20 + 1)06₉

= 5(13)(20)(2•9 + 3)06₉

= 5(13)(20 + 2)306₉

= 5(13)(2•9 + 4)306₉

= 5(13 + 2)4306₉

= 5(1•9 + 6)4306₉

= (5 + 1)64306₉

= 664306₉

4 0
3 years ago
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