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anzhelika [568]
2 years ago
15

An element with mass 430 grams decays by 27.4% per minute. How much of the element is remaining after 19 minutes, to the nearest

10th of a gram?
Mathematics
1 answer:
nadya68 [22]2 years ago
7 0
The equation for exponential decay is y=a*b^x, where <em>a</em> is the initial amount, <em>b</em> = 1 + <em>r</em> (the growth rate as a decimal number) and <em>x</em> is the number of time periods (in this case, minutes).  Substituting the information we have:
y=430(1+-0.274)^1^9&#10;\\=430(1-0.274)^1^9&#10;\\=430(0.726)^1^9=0.98.  To the nearest tenth of a gram, this would be 1.0 grams.
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A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find
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Answer:

Approximately 68.5\; \rm mm.

Step-by-step explanation:

Convert the angle of this sector to radians:

\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}.

The formula s = r\, \theta relates the arc length s of a sector of angle \theta (in radians) to the radius r of this sector.

In this question, it is given that the arc length of this sector is s = 36\; \rm mm. It was found that \theta = 2.22 radians. Rearrange the equation s = r\, \theta to find the radius r of this sector:

\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}.

The perimeter of this sector would be:

\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}.

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2 years ago
A triangle has a sides (x) feet, (x+3) feet, and (x+5) feet. The perimeter is 99.5 feet What is the measure for the largest side
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Answer:

35.5 feet

Step-by-step explanation:

x + x + 3 + x + 5 = 99.5

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30.5 + 5 = 35.5 feet

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