Solve y = x + 4 for x, Ox=y - 4 Ox=y+ 4 Ox=-y + 4 Ox=-y

NOT A MATH QUESTION!!! JUST A LIFE QUESTION....

natka813 [3]

Monday- a. Red shirt, blue pants, white accesories b. Blue shirt, white pants, red assesories c. switch around a. and b.

Tuesday- (Not sure what you were like as a kid) but things I would suggest would be maybe be a tutu (if female), ruffles on shirts, Colorful shirts with lettering, colorful leggings, candy bracelets/ necklaces maybe?

Wednesday- (Don't know what decade day means) Maybe like oversized t-shirts/ hoodies, pastel, etc. probably anything to do with the 21st century

Thurday- Team t-shirts (if you have those), Black pants/shirt with red pants/shirt, you could put face paint with red and black under your eyes, Black and red tutus (sorry for so many tutu ideas) etc. etc.

Friday- If you don't like dresses than i'm guessing it means church clothes so try that domain maybe?

6 0

3 years ago

Y varies inversely with x, and k (the constant of variation) = 1.24. What is the value of y when x = 4.96?

V125BC [204]

Answer:= y = 0.25 to the nearest hundredth.

Step-by-step explanation:

In inverse variation, both variables move in opposite directions. This means that as variable 1 increases, variable 2 reduces and as variable 1 reduces, variable 2 increases.

Y varies inversely with x.

So as y increases, x reduces and as y reduces, x increases.

We would proceed by introducing a constant of variation, k

y = k/x

From the information given,

The constant of variation, k = 1.24

The value if x = 4.96

To find the value of y

y = k/x = 1.24/4.96

= 0.25 to the nearest hundredth.

6 0

3 years ago

PLEASE HURRY!50 POINTS ANS BRAILIEST

densk [106]

Answer:

A:

The decreasing value of car 1 can be represented by an exponential function and car 2 by a linear function

B:

Car 1: f(x) = $18500(0.94)^{x}$

Car 2: f(x) = 18500 - 1000x

C:

Car 1 would be $10600.40 after 9 years

Car 2 would be $9500.00 after 9 years

There is a significant difference of $1100.40 in value.

Step-by-step explanation:

$f(x) = ar^{x}\\f(0) = a = 18500\\f(x) = 18500r^{x}\\f(1) = 18500r = 17390\\r = \frac{17390}{18500} = 0.94\\f(x) = 18500(0.94)^{x}$

7 0

3 years ago

Justin rented a truck for one day. There was a base fee of $15.99, and there was an additional charge of 89 cents for each mile

Tamiku [17]

266.08- 15.99 (get it down to its base)
250.09/.89= 281 miles.

8 0

3 years ago

Read 2 more answers

In order to ensure efficient usage of a server, it is necessary to estimate the mean number

juin [17]

Answer:

a. [36.19;39.21]

b. Reject the null hypothesis. The population mean of users that are connected at the same time is greater than 35.

Step-by-step explanation:

Hello!

Your study variable is,

X: "number of users of one server at a time"

The objective is to estimate the mean, for this, a sample of n=100 times was taken and the standard deviation S= 9.2 and the sample mean is X[bar]= 37.7 were calculated.

You need to study the population mean, for this you need your variable to have at least normal distribution. Since you don't have information about its distribution, but the sample is big enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample mean X[bar] to normal:

X[bar]≈N(μ;σ²/n)

a. With this approximation, you can construct the 90% Confidence Interval using the approximate Z

[X[bar] ± $Z_{1-\alpha /2}$ * S/√n]

$Z_{1-\alpha /2}$ = $Z_{0.95}$ = 1.64

[37.7± 1.64* 9.2/√100]

[36.19;39.21]

b. You need to test if the population mean is greater than 35 with a level of significance of 1%.

The hypothesis is:

H₀: μ ≤ 35

H₁: μ > 35

α: 0.01

This is a one-tailed test so you have only one critical level (right tail):

$Z_{1\alpha } = Z_{0.99} = 2.33$

This means that if the value of the calculated statistic is equal or greater than 2.33 you will reject the null Hypothesis.

If the value is less than 2.33 you will support the null hypothesis.

The statistic is:

Z= X[bar] - μ = 37.7 - 35 = 2.93

S/√n 9.2/10

The value 2.93 > 2.33, so you reject the null hypothesis. This means that the population mean of users that are connected at the same time is greater than 35.

Note: To make the decision using the interval calculated on a), the hypothesis should have been two-tailed and the confidence and significance levels complementary.

I hope it helps!

7 0

3 years ago

Solve y = x + 4 for x, Ox=y - 4 Ox=y+ 4 Ox=-y + 4 Ox=-y - 4