18 students at woodworth school. 1/2 as many girls as boys. how many girls

Mathematics

2 answers:

Ganezh [65]4 years ago

8 0

9 girls and 9 boys equals 18 students

alex41 [277]4 years ago

5 0

To solve this problem, let's write what we know:

18 students.

1/2 as many girls as boys.

So however many girls they have, there will be twice as many boys.

Let's try it out:

If there were 9 girls, there would be 18 boys, and a total of 27 students. That's too much.

If there were 4 girls, there would be 8 boys, and a total of 12 students. That's not enough.

Can you see a pattern? Try one more.

If there were 6 girls, there would be 12 boys, and a total of 18 students. Perfect!

You might be interested in

What is the closest length of RT?

almond37 [142]

Answer: 14

Step-by-step explanation:

Since it is a right angles triangle , Pythagoras theorem will come into play,which states that;

the square of the hypotenuses = square of the adjacent + square of the opposite , that is

$22^{2}$ = $(RT)^{2}$ + $17^{2}$

Therefore:

$(RT)^{2}$ = $22^{2}$ - $17^{2}$

$(RT)^{2}$ = 484 - 289

$(RT)^{2}$ = 195

RT = $\sqrt{195}$

RT = 13.96

RT≈ 14

6 0

3 years ago

Read 2 more answers

Solve |x+2|=10<br> Please help

Anvisha [2.4K]

x = 8, --- 12

I hope this helped :))))))))))))))))))

7 0

3 years ago

Read 2 more answers

10x +2y = 64

Musya8 [376]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}10x+2y=64&\text{multiply both sides by 2}\\3x-4y=-36\end{array}\right\\\underline{+\left\{\begin{array}{ccc}20x+4y=128\\3x-4y=-36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad23x=92\qquad\text{divide both sides by 2}\\.\qquad x=4\\\\\text{put the value of x to the first equation:}\\\\10(4)+2y=64\\40+2y=64\qquad\text{subtract 40 from both sides}\\2y=24\qquad\text{divide both sides by 2}\\y=12$