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anastassius [24]
3 years ago
10

Find the difference between of the greatest and smallest 5 digit number​

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
8 0

Answer:

Step-by-step explanation:

The largest 5-digit number is 99999 and the smallest 5-digit number is 10000. If it was mentioned that the largest unique 5-digit number then it would have been 98765 and the smallest 5-digit number would have been 10234.

Hope this answer helps you :)

Have a great day

Mark brainliest

Sav [38]3 years ago
6 0

Answer:

89,999

Step-by-step explanation:

Greatest 5-Digit Number is 99,999

Smallest 5-Digit Number is 10,000

Difference:

99,999 - 10,000 = 89,999

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Graph.<br><br><br> y+1=1/3(x−3)<br><br> (Please tell me where to mark it)
Lana71 [14]

I will give you 2 points.

y+1=1/3(x-3)

y+1=1/3x-1

y=1/3x-2

If x=0:

y=0-2

y=-2

(0,-2)

If x=3

y=3*1/3-2

y=1-2

y=-1

(3,-1)


3 0
4 years ago
Can y’all help me please i don’t get a thing about this i’m too shy to ask for help?
Roman55 [17]
U just graph em homie
7 0
3 years ago
Can someone please help me solve this
lozanna [386]

Answer:

Step-by-step explanation:

It saids evaluate given the three different functions below: The graph f(x), the equation g(x) and the table h(x)

3 0
2 years ago
Find a point-slope form for the line that satisfies the stated conditions.
Yakvenalex [24]

Answer:

y=6x+41

Step-by-step explanation:

y-5=6(x+6)

y=6x+41

3 0
3 years ago
The standard form of the equation of a parabola is y= x2 - 6x + 14.
Bas_tet [7]
<h3><u>Option C</u></h3><h3><u>The vertex form of the equation is:</u></h3>

y = (x - 3)^2 + 5

<em><u>Solution:</u></em>

<em><u>The vertex form of equation is given as:</u></em>

y = a(x- h)^2 + k

Where, (h, k) is the vertex

Given that,

y = x^2 - 6x + 14

We have to find the vertex form of equation

Step 1:

Complete the square for x^2 - 6x + 14

\text{ Use the form } ax^2 + bx + c \text{ to find values of a, b, c }

a = 1

b = -6

c = 14

Consider the vertex form of a parabola.

a(x + d)^2 + e ----- eqn 1

Substitute the values of  a and b into following:

d = \frac{b}{2a}\\\\d = \frac{-6}{2 \times 1}\\\\d = -3

Find the value of "e" using following formula:

e = c - \frac{b^2}{4a}\\\\e = 14 - \frac{(-6)^2 }{4 \times 1}\\\\e = 14 - 9\\\\e = 5

Substitute the values of a, d, e in eqn 1

y = 1(x -3)^2 + 5\\\\y = (x - 3)^2 + 5

Thus vertex form form is found. Option C is correct

3 0
3 years ago
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