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3 years ago

12

So i need help on one of my homework questions. The problem is, On his first 2 tests Nate`s average score was 80 percent. On his

next 3 tests Nate`s average score was 90 percent. What was his average score for all 5 tests? I need help on how to solve this.

1 answer:

Anvisha [2.4K]3 years ago

7 0

His average for all 5 tests would by 86% because 80 + 80 = 160 and 160 + (90 x 3) = 430 and 430 divided by 5 = 86%.

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Edward's school is 132 miles away from his home . He goes by car to school and back. The car consumed 4 gallons of gas taking hi

mixer [17]

Total distance is 132 miles x 2 times/day x 5 days = 1320 miles
That used 4 gallons of fuel, so 1320 miles/4 gallons = 330 miles per gallon

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3 years ago

A cash register contains $10 bills and $20 bills with a total value of $520. If there are 32 bills total, then how many of each

ohaa [14]

12 is the number of $10 bills

20 is the number of $20 bills

<u><em>Step-by-step explanation:</em></u>

<u><em /></u>

Hello,

<u>Let's note</u>

a the number of $10 bills

b the number of $20 bills

The total value is $520 so we can write the first equation (1)

$\boxed{\sf 10a \ + \ 20b \ = \ 520 }$

We know that there are 32 bills in total so we can write the second equation (2)

$\boxed{\sf a \ + \ b \ = \ 32 }$

(1) - 10*(2) gives

10a + 20b - 10(a+b) = 520 - 320 = 200

10a + 20b - 10a - 10b = 10b = 200

So b = 200/10=20

and then from (2) a = 32 - 20 = 12

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0

3 years ago

Solve the system by substitution.<br> 4y =<br> 5x -10y =-50

Trava [24]

Answer:

$x = -20 ; y =-5$

Step-by-step explanation:

Eqn. 1 ----> 4y = x

Eqn. 2 ----> 5x-10y = -50

(Simplifying eqn.2 further)

$=>5(x-2y)=-50$

$=>x-2y=\frac{-50}{5} =-10$

(Substituting the value of x from eqn. 1)

$=>4y-2y=-10$

$=>2y=-10$

$=>y =\frac{-10}{2} =-5$

Now, substituting the value of y in eqn. 1 ,

$x = 4*(-5)=-20$

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3 years ago

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Sav [38]

Answer:

420 (lol)

Step-by-step explanation:

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4 years ago

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DerKrebs [107]

Answer:

∅1=15°,∅2=75°,∅3=105°,∅4=165°,∅5=195°,∅6=255°,∅7=285°,

∅8=345°

Step-by-step explanation:

Data

r = 8 sin(2θ), r = 4 and r=4

iqualiting; 8.sin(2∅)=4; sin(2∅)=1/2, 2∅=asin(1/2), 2∅=30°, ∅=15°

according the graph 2, the cut points are:

I quadrant:

0+15° = 15°

90°-15°=75°

II quadrant:

90°+15°=105°

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III quadrant:

180°+15°=195°

270°-15°=255°

IV quadrant:

270°+15°=285°

360°-15°=345°

No intersection whit the pole (0)

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4 years ago