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4 years ago

Simplify the following. (a) 3(-3 + 5x) - 1 (4 - 4x) (b) 3 squareroot 64 x^15 y^3 -2(-15 e^5 t/30 e^-2 t^-3)^0

Mathematics

1 answer:

Kaylis [27]4 years ago

6 0

Answer:

a. 19x-13 b. $2(32x^{15}y^{3}-1).$

Step-by-step explanation:

a. 3(-3+5x)-1(4-4x) = -9+15x-4+4x = 15x+4x-9-4 = 19x-13.

b. $64x^{15}y^{3}-2(-15e^{5}\frac{t}{30}e^{-2}t^{-3})^{0}$

= $64x^{15}y^{3}-2 = 2(32x^{15}y^{3}-1).$

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Helppp and explain too

kozerog [31]

Answer:

the first option

Step-by-step explanation:

I have attached the explanation. hope this help

5 0

3 years ago

Determine two pairs of polar coordinates for (3,-3) when 0

Xelga [282]

The two pairs of polar coordinates for the given point (3, -3) with 0° ≤ θ < 360° are (3√2, 135°) and (3√2, 315°).

<h3>What is a polar coordinate?</h3>

A polar coordinate is a two-dimensional coordinate system, wherein each point on a plane is typically determined by a distance (r) from the pole (origin) and an angle (θ) from a reference direction (polar axis).

Next, we would determine the distance (r) and angle (θ) as follows:

r = √(3² + (-3)²)

r = √(9 + 9)

r = 3√2.

θ = tan⁻¹(-3/3)

θ = tan⁻¹(-1)

θ = 3π and 7π/4 (second and fourth quadrants).

Converting to degrees, we have:

θ = 135° and 315°.

Read more on polar coordinates here: brainly.com/question/3875211

#SPJ1

Complete Question:

Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°

5 0

2 years ago

Find the minimum or maximum value of the function g(x)= -(x-2)^2-3

Nady [450]

Neato

assuming you mean
$g(x)=-1(x-2)^2-3$
remember
in form
$f(x)=a(x-h)^2+k$
a is leading coficient
(h,k) is vertex
k will be the minimum or max value of the function
if a is positive, then the parabola opens up and k is minimum
if a is negative, then the parabola opens down and k is max

given
$g(x)=-1(x-2)^2-3$
a is negative
the parabola opens down and k is the max value
it is -3
the max value is -3, which occors at x=2
g(2)=-3 is max

3 0

3 years ago

Sin0=12/37 find tan0

alexira [117]

Answer:

$\large{ \tt{❃ \: EXPLANATION}} :$

We're provide - Sin θ = $\frac{12}{37}$ which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = $\tt{ \frac{p}{h}}$ ] . We're asked to find out tan θ ].

$\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :$

$\large{ \tt{❊ \: {h}^{2} = {p}^{2} + {b}^{2} }}$

$\large{ \tt{⇢ {p}^{2} + {b}^{2} = {h}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = {h}^{2} - {p}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = {37}^{2} - {12}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = 1369 - 144}}$

$\large{ \tt{ ⇢{b}^{2} = 1225}}$

$\large{ \tt{⇢ \: b = \sqrt{1225}}}$

$\large{ \tt{⇢ \: b = 35 \: \text {units}}}$

Now , We know - Tan θ= $\tt{ \frac{perpendicular}{base} }$ . Just plug the values :

$\large{ \tt{➝ \: Tan \: \theta = \frac{p}{b} = \boxed{ \tt{ \frac{12}{35} }}}}$

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5 0

3 years ago

On a fishing excursion, jeannie keeps 1/4 of the fish she catches and releases the remainder of the fish back into the lake. if

postnew [5]

To find 1/3 of 3/4 we divide the fraction by 3 which is equal to 1/4 or alternatively we can multiply the denominator by 3 which gives us 3/12 (1/4=3/12)
So 3/12 of the realesed fish are trout

To find 2/3 of 1/4 we need to first divide 1/4 by 3 which is equal to multiplying the denominator times 3 which gives us 1/12 and then we multiply by 2 which gives us 2/12
So 2/12 of the kept fish are trout

To find the total amount we add 2/12 and 3/12
3/12+2/12= 5/12

ANSWER:
5/12 of the fish she catches are trout

7 0

3 years ago