Answer:
x+5x=84
6x=84
6x/6=84/6
x=14
so therefore
14+5(14)
14+70
The numbers are 14 and 70
2a + 3b = 6 --> Equation 1
5a + 2b = 4 --> Equation 2
Equation 1 * 5 --> 10a + 15b = 30
Equation 2 * 2 --> 10a + 4b = 8
Equation 1 - Equation 2 --> 11b = 22 --> b = 2
Sub b=2 in Equation 1 (or 2, either works):
2a + 3b = 6
2a + 3(2) = 6
2a + 6 = 6
2a = 0
a = 0
b = 2, a = 0
Answer: a) Mean = 5, Median = 5
b) Mean = 15, Median = 5
c) Due to presence of outlier i.e. 99.
Step-by-step explanation:
Since we have given that
1,2,3,4,5,6,7,8,9
Here, n = 9 which is odd
So, Mean would be

Median = 
If 9 is replaced by 99,
1,2,3,4,5,6,7,8,99
So, mean would be

Median would be same as before i.e. 5
The mean is neither central nor typical for the data due to outlier i.e. 99
Hence, a) Mean = 5, Median = 5
b) Mean = 15, Median = 5
c) Due to presence of outlier i.e. 99.
Answer:
6e+7
Step-by-step explanation:
divide the volume value by 1e+6