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3 years ago

What is the x-intercept of the line with this equation 13x+y=−15 ? Enter your answer in the box. ( , 0)

Mathematics

1 answer:

Nastasia [14]3 years ago

4 0

Answer: The required x-intercept of the given line is $\left(-\dfrac{15}{13},0\right).$

Step-by-step explanation: We are given to find the x-intercept of the line with the following equation :

$13x+y=-15~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We know that

x-intercept of a line is a point on the line where the line crosses the x-axis, that is y co-ordinate is 0.

Substituting y = 0 in equation (i), we get

$13x+y=--15\\\\\Rightarrow 13x+0=-15\\\\\Rightarrow 13x=-15\\\\\Rightarrow x=-\dfrac{15}{13}.$

Thus, the required x-intercept of the given line is $\left(-\dfrac{15}{13},0\right).$

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Answer:

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If you graph there would be two different regions. The first one would be

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Step-by-step explanation:

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Which angles are coterminal with an angle drawn in standard position measuring 282°?

vampirchik [111]

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−438°, -78°, 642°

Step-by-step explanation:

Given angle:

282°

To find the co-terminal angles of the given angle.

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Co-terminal angles are all those angles having same initial sides as well as terminal sides.

To find the positive co-terminal of an angle between 360°-720° we will add the angle to 360°

So, we have: $282\°+360\°=642\°$

To find the negative co-terminal of an angle between 0° to -360° we add it to -360°

So, we have: $282\°-360\°=-78\°$

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So, we have: $282\°-720\°=-438\°$

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