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3 years ago

Please help thank you!

Mathematics

1 answer:

Dvinal [7]3 years ago

4 0

first one is A.
the sencond one is D maybe
ther third one is D again
hope these are right

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Order from least to greatest

RUDIKE [14]

Do them backwards and you will get the answer

5 0

3 years ago

Read 2 more answers

Two sides of a triangle are 8 m and 9 m in length and the angle between them is increasing at a rate of 0.06 rad/s. Find the rat

Lelechka [254]

<h2>Rate at which area is increasing is 1.08 m²/s.</h2>

Step-by-step explanation:

Area of triangle is with side a and b and angle C between them is given by

A = 0.5 ab SinC

Here we need to find how area changes with a and b fixed and C is changing,

$\frac{dA}{dt}=\frac{d}{dt}\left (0.5 absinC\right )\\\\\frac{dA}{dt}=0.5ab\frac{d}{dt}\left (sinC\right )\\\\\frac{dA}{dt}=0.5abcosC\frac{dC}{dt}$

We have

a = 8 m

b = 9 m

$C=\frac{\pi}{3}rad\\\\\frac{dC}{dt}=0.06rad/s$

Substituting

$\frac{dA}{dt}=0.5\times 8\times 9\times cos\left ( \frac{\pi}{3}\right )\times 0.06\\\\\frac{dA}{dt}=1.08m^2/s$

Rate at which area is increasing is 1.08 m²/s.

4 0

3 years ago

Kaitlin has four and two-thirds berry pies. She is going to share it equally among 12 people. How much pies will each person get

Ulleksa [173]

Answer:

7/18

Step-by-step explanation:

4 2/3=14/3

(14/3)/12=14/36

reduces to

7/18

3 0

2 years ago

There are 220 people who voted at the 6th grade meeting.Sixty percent of the voters are in favor of changing the school mascot.H

Amiraneli [1.4K]

60% of 220 is 132.
220 -132 = 88

88 people.

4 0

3 years ago

Assume that f is continuous on [-4,4] and differentiable on (-4,4). The table gives some values of f'(x) x: -4, -3, -2, -1, 0, 1

kondaur [170]

$f$ will be increasing on the intervals where $f'(x)>0$ and decreasing wherever $f'(x)$ . Local extrema occur when $f'(x)=0$ and the sign of $f'(x)$ changes to either side of that point.

$f'(x)$ is positive when $x$ is between -4 and some number between -2 and -1, and also 2 (exclusive) and 4, so you can estimate that $f(x)$ is increasing on the intervals [-4, -2] and (2, 4].

$f'(x)$ is negative when $x$ is between some number between -2 and -1, up to some number less than 2. So $f(x)$ is decreasing on the interval [-1, 1].

You then have two possible cases for extrema occurring. The sign of $f'(x)$ changes for some $x$ between -2 and -1, and again to either side of $x=2$ .

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3 years ago