The population of a school of fish increases at a rate of 12% per month. There are currently 500 fish in the school. Find the am
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Solution :
We know that
At least one mean is different form the others (claim)
We need to find the critical values.
We know k = 3 , N = 35, α = 0.05
d.f.N = k - 1
= 3 - 1 = 2
d.f.D = N - k
= 35 - 3 = 32
SO the critical value is 3.295
The mean and the variance of each sample :
Goust Jet red Cloudtran
The grand mean or the overall mean is(GM) :
= 52.1714
The variance between the groups
= 63.55714
The Variance within the groups
= 20.93304
The F-test statistics value is :
= 3.036212
Now since the 3.036 < 3.295, we do not reject the null hypothesis.
So there is no sufficient evidence to support the claim that there is a difference among the means.
The ANOVA table is :
Source Sum of squares d.f Mean square F
Between 127.1143 2 63.55714 3.036212
Within 669.8571 32 20.93304
Total 796.9714 34