S. pyogenes causes Strep throat, Varicella zoster causes varicella, Papillomavirus causes HPV, E. faecium cause urinary tract infection B. burgdorferi causes Lyme disease and B. pertussis causes Pertussis.
<h3>What is Bordetella pertussis?</h3>
Bordetella pertussis is a bacteria from the genus Bordetella that causes a respiratory disease known as Pertussis.
Moreover, Bordetella burgdorferi is another bacteria from genus Bordetella that causes Lyme disease, an illness whose symptoms include fever and fatigue.
In conclusion, Streptococcus pyogenes causes Strep throat, Varicella zoster causes varicella, Papillomavirus causes HPV, Enterococcus faecium cause urinary tract infection Borrelia burgdorferi causes Lyme disease and Bordetella pertussis causes Pertussis.
Learn more about Lyme disease here:
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The answer would be A: 1:16
This is because the letters mean:
Y: yellow
y: green
S: round
s: wrinkled
Thus, because the lowercase letters represent recessive alleles, both letters must be lowercase in order for the gene to show in the offspring.
So, if you wanted green, wrinkled, seeds, the only option (in letter form) would represented by:
ssyy
Therefore, because there is only one block with those letters, and sixteen blocks total, the ratio is 1:16.
the first answer as blood needs to be oxygenated to be passes round the body then when its deoxgenated it will return to the heart to be pumped around the body again
If you drink methanol or touch it or even smell it really close you can get really sick or you die because is like gasoline so If you drink ethanol you die to even that's made out of sugar cane there's another substances in it so if you drink it you die.
Answer:
C) 91%
Explanation:
First,
Express the Dominant phenotype as homozygous dominant(BB) and heterozygous(Bb).
Based on hardy-Weinberg equilibrium,
homozygous dominant (BB) Brown eye individuals will have the following percentage
B × B
(Where B = 70%)
70% × 70%
= 49%
heterozygous dominant (Bb) Brown eye individuals will have the following percentage
Using 2 × B × b (where B =70% and b = 30%)
2 × 70% × 30%
= 42%
The proportion of the subsequent generation with brown eyes
(homozygous dominant, BB + heterozygous dominant, Bb)
= 49% + 42%
= 91%
