In this kind of population, the make up of the population's gene pool will remain virtually the same as long as these conditions hold. In this kind of situation, no evolution can take place, all thing will remain the same. For evolution to occur, competition must exist.
Answer:
a) How many genotypes will occur in F2
--The genotypes would be- AA Aa aa BB Bb bb CC Cc cc DD Dd dd EE Ee ee (15 genotypes)
Reason-
This is because, after crossing the parents, the F1 generation would all be Heterozygous dominant since one parent is homozygous dominant, while the other is homozygous recessive.
b) 25% of all F2 genotypes would be recessive across the 5 loci
Reason-
This is because each loci would produce only a 25% chance for a recessive trait, which would results to a general probability of 25% also.
c) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aaBBccDDEE
d) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aabbccddEE
Answer:
Explanation:
The basis for the inverse relationship between number of matured HDL in circulation and and cardiovascular disease is that when new HDL entertainment circulation they mature by picking up extra cholesterol until they become mature and high cholesterol level is a major cause of cardiovascular disease and atherosclerosis. The implication of this is that the more the number of matured HDL in circulation, the lower the cholesterol level in the blood thus the lower the risk of cardiovascular disease and atherosclerosis.
You can conclude that the father was either heterozygous for that trait or fully homozygous.
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