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ss7ja [257]
2 years ago
13

73 gram of HCl was filluted by adding 144gram of water.how many gram atom of hydrogen are present in the dilute acid?

Chemistry
1 answer:
agasfer [191]2 years ago
8 0

Mass of Hydrogen atoms : 18 g

<h3>Further explanation</h3>

Given

73 gram of HCl

144gram of H₂O

Required

Mass (gram) atom of Hydrogen

Solution

H atoms are in 2 compounds, H₂O and HCl, so we calculate their mass in each compound

  • mass H in H₂O :

\tt \dfrac{1}{36.5}\times 73=2~g

mass H in HCl :

\tt \dfrac{2}{18}\times 144=16~g

total mass = 2 g+ 16 g = 18 g

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45 neutrons

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For the closed system below: Cu(s) + 2Ag+(aq) 2Ag(s) + Cu2+(aq) How would you know if the system is at equilibrium?
zaharov [31]
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5 0
3 years ago
Any help with these questions would help i'm lost
SSSSS [86.1K]

Answer:

1.  31.25 mL

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3.  0.45 g/mL

Explanation:

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1.  You need volume (mL).  You have density (g/mL) and mass (g).  Divide mass by density.  You will cancel out mL and be left with g.

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2.  You are given grams and liters.  You need to find density with units g/L.  This means that you have to divide grams by liters.

(0.891 g)/(0.450 L) = 1.98 g/L

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5 0
3 years ago
Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron transfe
babunello [35]

Answer:

Oxidized and reducing agent: manganese.

Reduced and oxidizing agent: mercury.

Explanation:

Hello!

In this case, for the reaction:

Hg^{2+}(aq) + Mn^0(s)\rightarrow Hg(s) + Mn^{2+}(aq)

We keep in mind that the species that increase the oxidation state is the oxidized one whereas the one that decrease the oxidation state is the reduced one; therefore manganese is the oxidized one as well as the reducing agent because it goes from 0 to +2 and mercury the reduced one as well as the oxidizing agent because it goes from 2+ to 0.

Best regards

6 0
2 years ago
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