In the late 1 800s , experiments using cathode ray tubes led to the discovery of the

Chemistry

1 answer:

Mice21 [21]3 years ago

7 0

<em>In the late 1800's, experiments using cathode ray tubes led to the discovery of the;</em>

Electron(s)

<u>It was founded that many different metals release cathode rays, and that cathode rays were made of electrons, very small negatively charged particles.</u>

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What role does the wire play in voltaic cell?

Triss [41]

<h3><u>Answer;</u></h3>

a) It allows electrons to flow from the anode to the cathode.

<h3><u>Explanation</u>;</h3>

<em><u>Voltaic cell is an electrochemical cell in which a spontaneous chemical reaction produces the flow of electrons</u></em>.
Electrons are produced by the oxidation reaction occurring at the anode. Electrons flow through the conducting wire from the anode to the cathode. At the cathode these electrons are used to reduce copper(II) ions to copper atoms.
<em><u>A conducting wire or a wire play connects the two electrodes allowing electrons to flow from the anode to the cathode</u></em>.

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3 years ago

H2SO4 + Ba(OH)2à BaSO4 + H2O is an unbalanced chemical equation. What is the coefficient for sulfuric acid (H2SO4) when this equ

Ivanshal [37]

H₂SO₄ + Ba(OH)₂ -----> BaSO₄ + 2H₂O

Coefficient for sulfuric acid: 1

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3 years ago

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The following two compounds are constitutional isomers. Identify which of these is expected to be more acidic, and explain your

Vladimir [108]

Answer:

c. Compound 2 is more acidic because its conjugate base is more resonance stabilized

Explanation:

You haven't told us what the compounds are, so let's assume that the formula of Compound 1 is HCOCH₂OH and that of Compound 2 is CH₃COOH.

The conjugate base of 2 is CH₃COO⁻. It has two important resonance contributors, and the negative charge is evenly distributed between the two oxygen atoms.

CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺

The stabilization of the conjugate base pulls the position of equilibrium to the right, so the compound is more acidic than 1.