If the only perimeters are that the length has to be twice the width and less than 108 meters then there are an infinite amount of possible values for width. For example: 1.0002 and 2.0004 or 4 and 8. You can use an infinite amount of decimal places and therefore have an infinite amount of values.
The largest the width can be is the limit approaching 18 and it has to be greater than 0 tho
Answer:
Step-by-step explanation:
- Deposit = $5000
- Interest rate = 2% simple
- Time = 5 years
<u>Interest amount is:</u>
Answer:
r = 4
Step-by-step explanation:
The radius is always half the length of the diameter. In this case r = 4.
Possible dimensions:
40 x 1
20 x 2
4 x 10
5 x 8
since 10 is 6 more than 4, the length is 10 and the width is 4
Answer:
(x - [-1])² + (y - [-1])² = [13]
Step-by-step explanation:
If P and Q are the end-points of the diameter PQ, midpoint of the segment PQ will be the center of the circle. (Definition of the center of a circle)
Midpoint of a segment having extreme ends and
Coordinates of the center =
Since, extreme ends of the diameter are P(-4, -3) and Q(2, 1)
Center of the circle =
= (-1, -1)
Radius of the circle = Distance between the center and Q,
Since distance between the two points and is,
d =
Radius of the circle =
=
=
Equation of the circle will be,
(x - h)² + (y - k)² = r²
Where (h, k) is the center and 'r' is the radius of the circle,
(x - [-1])² + (y - [-1])² = [13]