A) area of square = base*height/////Triangle= 0.5*base*height
=(a^1/3*b^3/4)*(a^2/3*b^1/2)+(1/2*a^1/3*b^3/4*a^2/3*b^1/4)
=(a^1*b^5/4)+(1/2*a^1*b^1)
=(a*b^5/4)+(1/2*a*b)
B) a^2+b^2=c^2 (pythagorean theorem)
((27^2/3)*(16^1/4))^2 + (27^1/3)*(16^3/4)
(9*2=(18^2))=324 + (3*8= 24^2)= 576
324+576= 900
(900)^1/2= 30
hypotenuse= 30
C)( a^2/3*b^1/2)= 36*2(two sides)= 72
(a^1/3b^3/4)=24
(a^2/3*b^1/4)= 18
72+24+18+30(hypotenuse)= 144=perimeter
40 to the second power is 1600!
Answer:
h=6
Step-by-step explanation:
since 
is an equation for a line which intersects with the curve 
. The point of intersection, let's say 
, should satisfy the two equations. As a result, the value of y in the second equation can be replaced with the value of y in the first equation as the following,
therefore, the latter equation can be rewritten in a quadratic equation form as the following,
= 0
if the line is tangent to the curve, it means that the line touches the curve at one point, therefore the discernment of the second order equation will be equal to zero for the famous quadratic equation solution.
where 
and 
, as a result, the following equations can be deduced,
therefore, dividing both sides by 12
