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amm1812
4 years ago
8

qslant 50" align="absmiddle" class="latex-formula">

Mathematics
1 answer:
djverab [1.8K]4 years ago
3 0
80-2w \geq 50 \\  \\ 80 \geq 50+2w \\  \\ 80-50 \geq 2w  \\ \\  30 \geq 2w\quad \to  \dfrac{30}{2} \geq w\quad \to  \boxed{15 \geq w\to w\in   (-\infty, 15 ] }
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The Cunninghams are moving across the country. Mr. Cunningham leaves 3 hours before Mrs. Cunningham. If he averages 40mph and sh
svp [43]
Recall your d = rt, distance = rate * time

now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.

However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Mr Cunningham}&d&40&t\\
\textit{Mrs Cunningham}&d&80&t-3
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=40t\\
d=80(t-3)\\
----------\\
\boxed{40t}=80(t-3)
\end{cases}
\\\\\\
\cfrac{40t}{80}=t-3\implies \cfrac{t}{2}=t-3\implies t=2t-6\implies 6=2t-t
\\\\\\
6=t
5 0
3 years ago
A campground says campers can rend a square space taking up 225 square feet. How long would one side of the space be?
Helga [31]

Answer:

56.25 ft

Step-by-step explanation:

It is simple, since it is a square the sides are all the same length so you take A=area and divide it by four= h or w or l (height, width, length) so

225/4=56.25

3 0
3 years ago
Graph the function g.<br> f(x) = -2(x-4)² +4<br> g(x) = f(x) - 1<br> O
Sedaia [141]

Answer:

19

Step-by-step explanation:

fx=16+4

fx=20

gx= 20-1

gx=19

19

3 0
2 years ago
Using a linear approximation, estimate f(2.1), given that f(2) = 5 and f'(x) = √3x-1.
algol [13]

Answer:

f\left( {2.1} \right) \approx 5.22360.

Step-by-step explanation:

The linear approximation is given by the equation

                            {f\left( x \right) \approx L\left( x \right) }={ f\left( a \right) + f^\prime\left( a \right)\left( {x - a} \right).}

Linear approximation is a good way to approximate values of f(x) as long as you stay close to the point x= a, but the farther you get from x=a, the worse your approximation.

We know that,

a=2\\f(2) = 5\\f'(x) = \sqrt{3x-1}

Next, we need to plug in the known values and calculate the value of f(2.1):

{L\left( x \right) = f\left( 2 \right) + f^\prime\left( 2 \right)\left( {x - 2} \right) }=5+\sqrt{3(2)-1}(x-2) =5+\sqrt{5}(x-2)

Then

f\left( {2.1} \right) \approx 5+\sqrt{5}(2.1-2)\approx5.22360.

6 0
3 years ago
Please help I’ll mark you as brainliest if correct!
Pavlova-9 [17]

Answer:

3 ways

36÷6=6

36÷2=18

36÷3=12

maybe if not then 2 or 4

6 0
2 years ago
Read 2 more answers
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