(2x² - 8x - 10) ÷ 2 = 0
x² - 4x - 5 = 0
x² + x - 5x - 5 = 0
x(x+1) - 5(x+1) = 0
(x+1)(x-5) = 0
x+1 = 0 or x-5 = 0
x = -1 or x= 5
S = {-1;5}
The first graphed rational number is at the middle of -2 and -1, thus the number represented is
![-1 \frac{1}{2}](https://tex.z-dn.net/?f=-1%20%5Cfrac%7B1%7D%7B2%7D%20)
The second graphed number is five out of six places from from 0 to 1, thus the number graphed is
![0+ \frac{5}{6} = \frac{5}{6}](https://tex.z-dn.net/?f=0%2B%20%5Cfrac%7B5%7D%7B6%7D%20%3D%20%5Cfrac%7B5%7D%7B6%7D)
The difference between the two numbers can be represented as
![-1 \frac{1}{2} - \frac{5}{6}](https://tex.z-dn.net/?f=-1%20%5Cfrac%7B1%7D%7B2%7D%20-%20%5Cfrac%7B5%7D%7B6%7D%20)
or
![\frac{5}{6} -(-1 \frac{1}{2} )= \frac{5}{6} +1 \frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B6%7D%20-%28-1%20%5Cfrac%7B1%7D%7B2%7D%20%29%3D%20%5Cfrac%7B5%7D%7B6%7D%20%2B1%20%5Cfrac%7B1%7D%7B2%7D)
To find the difference,
![-1 \frac{1}{2} - \frac{5}{6} \\ \\ =-1 \frac{3+5}{6} \\ \\ =-1 \frac{8}{6} =-2 \frac{2}{6} \\ \\ =-2 \frac{1}{3}](https://tex.z-dn.net/?f=-1%20%5Cfrac%7B1%7D%7B2%7D%20-%20%5Cfrac%7B5%7D%7B6%7D%20%5C%5C%20%5C%5C%20%3D-1%20%5Cfrac%7B3%2B5%7D%7B6%7D%20%20%5C%5C%20%20%5C%5C%20%3D-1%20%5Cfrac%7B8%7D%7B6%7D%20%3D-2%20%5Cfrac%7B2%7D%7B6%7D%20%20%5C%5C%20%20%5C%5C%20%3D-2%20%5Cfrac%7B1%7D%7B3%7D%20)
Also,
Try to put x on one side.
Do y = 35+X
-35 -35
Now you have Y-35=x
Hope this helped
Answer:
in
Step-by-step explanation:
Let x be the side of square.
Length of box=8-2x
Width of box=15-2x
Height of box=x
Volume of box=![L\times B\times H](https://tex.z-dn.net/?f=L%5Ctimes%20B%5Ctimes%20H)
Substitute the values then we get
Volume of box=V(x)=![(8-2x)(15-2x)x=(15x-2x^2)(8-2x)](https://tex.z-dn.net/?f=%288-2x%29%2815-2x%29x%3D%2815x-2x%5E2%29%288-2x%29)
![V(x)=120x-30x^2-16x^2+4x^3](https://tex.z-dn.net/?f=V%28x%29%3D120x-30x%5E2-16x%5E2%2B4x%5E3)
![V(x)=4x^3-46x^2+120x](https://tex.z-dn.net/?f=V%28x%29%3D4x%5E3-46x%5E2%2B120x)
Differentiate w.r.t x
![V'(x)=12x^2-92x+120](https://tex.z-dn.net/?f=V%27%28x%29%3D12x%5E2-92x%2B120)
![V'(x)=0](https://tex.z-dn.net/?f=V%27%28x%29%3D0)
![12x^2-92x+120=0](https://tex.z-dn.net/?f=12x%5E2-92x%2B120%3D0)
![3x^2-23x+30=0](https://tex.z-dn.net/?f=3x%5E2-23x%2B30%3D0)
![3x^2-18x-5x+30=0](https://tex.z-dn.net/?f=3x%5E2-18x-5x%2B30%3D0)
![3x(x-6)-5(x-6)=0](https://tex.z-dn.net/?f=3x%28x-6%29-5%28x-6%29%3D0)
![(x-6)(3x-5)=0](https://tex.z-dn.net/?f=%28x-6%29%283x-5%29%3D0)
![x-6=0\implies x=6](https://tex.z-dn.net/?f=x-6%3D0%5Cimplies%20x%3D6)
![3x-5=0\implies x=\frac{5}{3}](https://tex.z-dn.net/?f=3x-5%3D0%5Cimplies%20x%3D%5Cfrac%7B5%7D%7B3%7D)
Again differentiate w.r.t x
![V''(x)=24x-92](https://tex.z-dn.net/?f=V%27%27%28x%29%3D24x-92)
Substitute x=6
![V''(6)=24(6)-92=52>0](https://tex.z-dn.net/?f=V%27%27%286%29%3D24%286%29-92%3D52%3E0)
Substitute x=5/3
![V''(5/3)=24(5/3)-92=-52](https://tex.z-dn.net/?f=V%27%27%285%2F3%29%3D24%285%2F3%29-92%3D-52%3C0)
Hence, the volume is maximum at x=![\frac{5}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B3%7D)
Therefore, the side of the square ,
in cutout that gives the box the largest possible volume.
Answer:
$2353 at 12.5% and $7647 at 8.25%
Step-by-step explanation:
I'll say a is the amount he invested in one market, and b is the amount in the other.
a + b = 10000, or b = 10000 - a
multiplying the investments with the percentages and adding them together will give the total earned interest.
(a × 0.125) + (b × 0.0825) = 925
0.125a + 0.0825b = 925
Use substitution to solve for a.
0.125a + 0.0825(10000 - a) = 925
0.125 a + 825 - 0.0825a = 925
0.0425a = 100
a = 2352.94
Use substitution to find b
b = 10000 - 2352.94
b = 7647.06
The questions are to the nearest dollar so round a and b.
$2353 and $7647