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evablogger [386]
3 years ago
11

PLS HELP! If a person has a weight of 600 N, how much will they weigh on the Moon?

Physics
2 answers:
nordsb [41]3 years ago
5 0

Explanation :

It is given that, the weight of the person on the earth is 600 N. The weight is equal to :

W = m g

where

g is the acceleration due to gravity on the earth, g = 10 m/s²

600\ N=m\times 10\ m/s^2

m = 60 kg

We know that the mass of an object remains constant everywhere.

The value of g on moon is, g' = 1.63 m/s²

So, W' = m g'

W'= 60\ kg\times 1.63 m/s^2    

W' = 97.8 N

Hence, the weigh on the moon is 97.8 N.                  

ad-work [718]3 years ago
3 0

They would weight 69N on the moon's surface.

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You toss a 0.40-kg ball at 9.0 ms/ to a 14-kg dog standing on an iced-over pond. The dog catches the ball and begins to slide on
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a)   v_{f} = 0.25 m / s  b) u = 0.25 m / s

Explanation:

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We will write the data

     m₁ = 0.40 kg

     v₁₀ = 9.0 m / s

     m₂ = 14 kg

     v₂₀ = 0

Initial

     po = m₁ v₁₀

Final

     p_{f} = (m₁ + m₂) vf

     po = pf

     m₁ v₁₀ = (m₁ + m₂) v_{f}

      v_{f} = v₁₀ m₁ / (m₁ + m₂)

      v_{f} = 9.0 (0.40 / (0.40 +14)

      v_{f} = 0.25 m / s

b) This is the reference frame of the center of mass of the system in this case the speed of this frame is the speed of the center of mass

      u = 0.25 m / s

In the direction of movement of the ball

c) Let's calculate the kinetic energy in both moments

Initial

     K₀ = ½ m₁ v₁₀² +0

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Final

     K_{f}= ½ (m₁ + m₂) v_{f}2

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    K_{f} = 0.45 J

   

    ΔK = K₀ -  K_{f}

    ΔK = 16.2-0.445

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These will transform internal system energy

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      v₁₀’= v₁₀ -u

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      v₂₀ ‘= v₂₀ -u

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Initial

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All initial kinetic energy is transformed into internal energy in this reference system

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