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evablogger [386]
3 years ago
11

PLS HELP! If a person has a weight of 600 N, how much will they weigh on the Moon?

Physics
2 answers:
nordsb [41]3 years ago
5 0

Explanation :

It is given that, the weight of the person on the earth is 600 N. The weight is equal to :

W = m g

where

g is the acceleration due to gravity on the earth, g = 10 m/s²

600\ N=m\times 10\ m/s^2

m = 60 kg

We know that the mass of an object remains constant everywhere.

The value of g on moon is, g' = 1.63 m/s²

So, W' = m g'

W'= 60\ kg\times 1.63 m/s^2    

W' = 97.8 N

Hence, the weigh on the moon is 97.8 N.                  

ad-work [718]3 years ago
3 0

They would weight 69N on the moon's surface.

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A thin, metallic spherical shell of radius 0.227 m has a total charge of 6.03 × 10 − 6 C placed on it.
KATRIN_1 [288]

Answer:

Explanation:

Given

radius r=0.227 m

Charge on surface Q=6.03\times 10^{-6} C

Point Charge inside sphere q=1.15\times 10^{-6} C

Electric Field at r=0.735 m

Treating Surface charge as Point charge and applying Gauss law

E_{total}A=\frac{q_{enclosed}}{\epsilon _0}

where A=surface area up to distance r

E_{total}=\frac{Q+q}{4\pi r^2}

E_{total}=\frac{6.03\times 10^{-6}+1.15\times 10^{-6}}{4\pi (0.735)^2\times 8.85\times 10^{-12}}

E_{total}=1.194\times 10^{5} N/C

3 0
4 years ago
Each blade of a fan has a radius of 11 inches. If the fan’s rate of turn is 1440o /sec, find the following. (a) The angular spee
notka56 [123]

Answer:

a) 24.43 radians per second

b) 268.73 inches per second

Explanation:

a) The angular speed of the fan on Celsius degrees/second is 1400, so we should convert that value to radians using the fact that 2π rad = 360 °C:

\omega = 1400\frac{C}{s}=1400\frac{C}{s}*\frac{2\pi\,rad}{360\,C}

\omega = 1400\frac{C}{s}=24.43\frac{rad}{s}

b) Linear speed on a point of the blade is related with angular speed of the fan by the equation

v=\omega r

with v linear speed, ω angular speed and r the radius of the blades. So:

v=(24.43\frac{rad}{s})(11 in)

Radians isn't really a unity; it is dimensionless so we can put it or not. So:

v=268.73\frac{in}{s}

3 0
4 years ago
A commuter airplane starts from an airport and takes theroute. The plane first flies to city A, located 175 km away in a directi
bearhunter [10]

Answer:

245.45km in a direction 21.45° west of north from city A

Explanation:

Let's place the origin of a coordinate system at city A.

The final position of the airplane is given by:

rf = ra + rb + rc    where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:

rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km

rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km

The module of this position is:

rf = \sqrt{rfX^2+rfY^2} = 245.45km

And the angle measure from the y-axis is:

\alpha =atan(rfX/rfY) = 21.45\°

So the answer is 245.45km in a direction 21.45° west of north from city A

6 0
3 years ago
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Answer:

The component of F along AB is equal to Fcos45

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Explanation:

7 0
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A: 132.9w because 2525\19 is how much energy transferred per second which is also known as the power
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