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3 years ago

A loud soundin heared at resonence why

Physics

1 answer:

zvonat [6]3 years ago

7 0

ANSWER :

Complete answer:

The resonance happens when the frequency of the vibration of one body matches with the frequency of vibration of another body. ... So, the loud music causes the air particles to vibrate and when we stand close to the source of loud music, it causes resonance and hence we feel our body shake or vibrate.

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How do scientists learn about the brain.

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3 years ago

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What is the velocity of the buggy? <br><br> At 20 seconds the buggy will have a position of ____ ?

lbvjy [14]

At 20 seconds it will be 12.6 because at 10 seconds it was as at approximately 6.3 so we times it by 2 to get the 20s

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3 years ago

magine an astronaut on an extrasolar planet, standing on a sheer cliff 50.0 m high. She is so happy to be on a different planet,

Mama L [17]

Answer:

$\Delta t=(\frac{20}{g'}+\sqrt{\frac{400}{g'^2}+\frac{100}{g'} } )-(\frac{20}{g}+\sqrt{\frac{400}{g^2}+\frac{100}{g} } )$

Explanation:

Given:

height above which the rock is thrown up, $\Delta h=50\ m$

initial velocity of projection, $u=20\ m.s^{-1}$

let the gravity on the other planet be g'

The time taken by the rock to reach the top height on the exoplanet:

$v=u+g'.t'$

where:

$v=$ final velocity at the top height = 0 $m.s^{-1}$

$0=20-g'.t'$ (-ve sign to indicate that acceleration acts opposite to the velocity)

$t'=\frac{20}{g'}\ s$

The time taken by the rock to reach the top height on the earth:

$v=u+g.t$

$0=20-g.t$

$t=\frac{20}{g} \ s$

Height reached by the rock above the point of throwing on the exoplanet:

$v^2=u^2+2g'.h'$

where:

$v=$ final velocity at the top height = 0 $m.s^{-1}$

$0^2=20^2-2\times g'.h'$

$h'=\frac{200}{g'}\ m$

Height reached by the rock above the point of throwing on the earth:

$v^2=u^2+2g.h$

$0^2=20^2-2g.h$

$h=\frac{200}{g}\ m$

The time taken by the rock to fall from the highest point to the ground on the exoplanet:

$(50+h')=u.t_f'+\frac{1}{2} g'.t_f'^2$ (during falling it falls below the cliff)

here:

$u=$ initial velocity= 0 $m.s^{-1}$

$\frac{200}{g'}+50 =0+\frac{1}{2} g'.t_f'^2$

$t_f'^2=\frac{400}{g'^2}+\frac{100}{g'}$

$t_f'=\sqrt{\frac{400}{g'^2}+\frac{100}{g'} }$

Similarly on earth:

$t_f=\sqrt{\frac{400}{g^2}+\frac{100}{g} }$

Now the required time difference:

$\Delta t=(t'+t_f')-(t+t_f)$

$\Delta t=(\frac{20}{g'}+\sqrt{\frac{400}{g'^2}+\frac{100}{g'} } )-(\frac{20}{g}+\sqrt{\frac{400}{g^2}+\frac{100}{g} } )$

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3 years ago

What is the biggest barrier to the use of renewable energy in the United States?

storchak [24]

The biggest barrier to the use of renewable energy in the United States is the Citizen opposition to negative environmental impact.
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3 years ago

A solenoid 83.0 cm long has a radius of 2.10 cm and a winding of 1600 turns; it carries a current of 3.60 A. Calculate the magni

Alenkinab [10]

Answer:

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Explanation:

given,

Length of solenoid (L)= 83 cm = 0.83 m

radius of the solenoid (r)= 2.10 cm = 0.021 m

number of turns (N)= 1600 turns

current (I)= 3.60 A

Using magnetic field formula

$B = \dfrac{\mu_0Ni}{L}$

$B = \dfrac{4 \pi \times 10^{-7} \times 1600 \times 3.6}{0.83}$

B = 0.0087 T

the magnitude of magnetic field inside the solenoid is equal to B = 0.0087 T

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3 years ago