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3 years ago

A loud soundin heared at resonence why

Physics

1 answer:

zvonat [6]3 years ago

7 0

ANSWER :

Complete answer:

The resonance happens when the frequency of the vibration of one body matches with the frequency of vibration of another body. ... So, the loud music causes the air particles to vibrate and when we stand close to the source of loud music, it causes resonance and hence we feel our body shake or vibrate.

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Suppose you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by

mylen [45]

Answer:

I must travel with a speed of 2.97 x 10^8 m/s

Explanation:

Sine the spacecraft flies at the same speed in the to and fro distance of the journey, then the time taken will be 6 months plus 6 months

Time that elapses on the spacecraft = 1 year

On earth the people have advanced 120 yrs

According to relativity, the time contraction on the spacecraft is gotten from

$t$ = $t_{0} /\sqrt{1 - \beta ^{2} }$

where

$t$ is the time that elapses on the spacecraft = 120 years

$t_{0}$ = time here on Earth = 1 year

$\beta$ is the ratio v/c

where

v is the speed of the spacecraft = ?

c is the speed of light = 3 x 10^8 m/s

substituting values, we have

120 = 1/ $\sqrt{1 - \beta ^{2} }$

squaring both sides of the equation, we have

14400 = 1/ $(1 - \beta ^{2} )$

14400 - 14400 $\beta ^{2}$ = 1

14400 - 1 = 14400 $\beta ^{2}$

14399 = 14400 $\beta ^{2}$

$\beta ^{2}$ = 14399/14400 = 0.99

$\beta = \sqrt{0.99}$ = 0.99

substitute β = v/c

v/c = 0.99

but c = 3 x 10^8 m/s

v = 0.99c = 0.99 x 3 x 10^8 = 2.97 x 10^8 m/s

6 0

3 years ago

Which equation is used to calculate the magnetic force on a charge moving in a magnetic field?

JulijaS [17]

The force is perpendicular to the plane formed by v and B. Since the force is zero if v is parallel to B, charged particles often follow magnetic field lines rather than cross them.

B) F = |q|vBsin

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3 years ago

Read 2 more answers

Insulators are materials that reduce heat flow. Nature uses many types of insulation to protect animals from losing too much hea

katrin2010 [14]

Answer:

This has all the answer (Data sheet, graph, answers to the questions, and the summary) :)

6 0

3 years ago

Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin

Zarrin [17]

Answer:

$\rm 9.186\times 10^{-7}\ C.$

Explanation:

Given:

Diameter of the plates of the capacitor, D = 21 cm = 0.21 m.
Distance of separation between the plates, d = 1.0 cm = 0.01 m.
Minimum value of electric field that produces spark, $\rm E=3\times 10^6\ N/C.$

When the dimensions of the plate of the capacitor is comparatively much larger than the distance of separation between the plates, then, according to the Gauss' law of electrostatics, the value of the electric field strength in the region between the plates of the capacitor is given by

$\rm E=\dfrac{\sigma}{\epsilon_o}.$

where,

$\rm \sigma$ = surface charge density of the plate of the capacitor = $\dfrac qA$ .

$\rm q$ = magnitude of the charge on each of the plate.
$\rm A$ = surface area of each of the plate = $\rm \pi \times (Radius)^2=\pi \times\left ( \dfrac{D}{2}\right )^2= \pi \times \left ( \dfrac{0.21}{2}\right )^2=3.46\times 10^{-2}\ m^2.$
$\epsilon_o$ = electrical permittivity of free space, having value = $8.85\times 10^{-12}\rm \ C^2N^{-1}m^{-2}.$

For the minimum value of electric field that produces spark,

$\rm E = \dfrac{q}{A\epsilon_o}\\\Rightarrow q = E\ A\epsilon_o\\=3\times 10^6\times 3.46\times 10^{-2}\times 8.85\times 10^{-12}\\=9.186\times 10^{-7}\ C.$

It is the maximum value of the magnitude of charge which can be added up to each of the plates of the capacitor.

4 0

3 years ago

Which of the following would act as a barrier to sound waves?

Y_Kistochka [10]

Headphones and earplugs

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3 years ago