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3 years ago

10. According to Newton's First Lawy , if a box is pushed with no external resistance, what will the action of the box be ?

Physics

2 answers:

Fantom [35]3 years ago

5 0

Answer:

The body will move farther away from its state of rest

Explanation:

According to Newton's first law of motion, a body will be in its position of rest unless acted upon by an unbalanced force.

A box pushed with no external resistance will therefore tends to move away from its state of rest to another position due to the effect if the force acted on the body.

kati45 [8]3 years ago

4 0

Explanation:

According to Newton's First Law of motion, if a box is pushed with no external resistance, the box will keep on moving due to the absence of external force. It might gets stopped due to frictional force that is acting between the surface and the ball. The first law of motion is also known as law of inertia. the magnitude of force acting on the object is given by second law of motion.

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Calculate the index of refraction for a medium in which the speed of light is 2.1x 108 m/s. The speed of light in vacuum is 3x10

strojnjashka [21]

Answer:

n = 1.42

Explanation:

The refractive index for a medium is given by the ratio of the speed of light in vacuum to the speed of light in a medium.

$n=\dfrac{c}{v}\\\\n=\dfrac{3\times 10^8}{2.1\times 10^8}\\\\n = 1.42$

So, the refractive index of the medium is 1.42.

5 0

3 years ago

A 0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 N/m. The simple harmonic

miss Akunina [59]

Answer:

0.07756 m

Explanation:

Given mass of object =0.20 kg

spring constant = 120 n/m

maximum speed = 1.9 m/sec

We have to find the amplitude of the motion

We know that maximum speed of the object when it is in harmonic motion is given by $v_{max}=A\omega$ where A is amplitude and $\omega$ is angular velocity

Angular velocity is given by $\omega=\sqrt{\frac{k}{m}}$ where k is spring constant and m is mass

So $v_{max}=A\sqrt{\frac{k}{m}}$

$A=V_{max}\sqrt{\frac{m}{k}}=1.9\times \sqrt{\frac{0.2}{120}}=0.07756 \ m$

3 0

3 years ago

Read 2 more answers

What is the momentum of an object that is moving in a straight line at a speed of 10 m/s and has a mass of 10 kilograms?

Aleksandr-060686 [28]

The momentum of an object is given by the product between its mass and its velocity:
$p=mv$
where m is the mass and v the velocity.

For the object in our problem, m=10 kg and v=10 m/s, therefore its momentum is
$p=mv=(10 kg)(10 m/s)=100 kg m/s$
So, the correct answer is B).

8 0

2 years ago

What will be the acceleration of a 40-kilogram object that is pushed with a net force of 80 newtons?

ratelena [41]

= 80 N/40 kg
= 2 m/s 2

4 0

2 years ago

Answer for a thanks

mariarad [96]

Well, if your question is how light affects plants,

then you would want to design an experiment that plays aruond with the amount of light a plant gets

thus the thing changing (or variable) would be amount of light

7 0

3 years ago