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3 years ago

An object is five focal lengths from a concave mirror.how do the object and image heights compare?

1 answer:

7 0

An object distance is presented as s = 5f and we know that the mirror equation relates the image distance to the object distance and the focal length.

The mirror equation is 1/f = 1/s + 1/s’ where the variable f stands for the focal length of the mirror. Variable (s) represents the distance between the mirror surface and the object and the variable (s’) represents the distance between the mirror surface and the image.

In addition, a concave mirror will have a positive focal length (f) and a convex mirror will have a negative focal length (f).

Now, we then have 1/f = 1/5f + 1/s’ which is s’ = 5f/4

Then we get the magnification ratio that expresses the size or amount of magnification or reduction of the object or image and to get the magnification, we use this equation: M= s’/s

M= 5f/4x5f

s’ = 1/4s

Therefore, the image height is one fourth of the object height

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A 5.18x10^4 kg railroad car moves on a frictionless horizontal rails until it hits a horizontal spring stopper with a force cons

nalin [4]

Answer:

The initial velocity of the cart was 0.91m/s.

Explanation:

When the car comes to a stop it has delivered all of its kinetic energy to the spring; therefore,

$\dfrac{1}{2}kx^2 = \dfrac{1}{2} mv^2$

solving for $v$ we get:

$v = x\sqrt{\dfrac{k}{m} },\\$

we put in $k = 4.21*10^{5}N/m$ , $m = 5.18*10^{4}kg$ , and $x = 0.32m$ to get:

$v = (0.32m)\sqrt{\dfrac{4.21*10^5}{5.18*10^4} },\\$

$\boxed{v = 0.91m/s.}$

4 0

4 years ago

If the temperature increases in a sample of gas at constant volume, then its. . a. volume increases. b. pressure decreases. c. p

kicyunya [14]

If the temperature increases in a sample of gas at constant volume, then its pressure increases. The increase in temperature makes the molecule hit the walls of the container faster. The correct option among all the options that are given in the question is the third option or option "c". I hope the answer helps you.

3 0

3 years ago

Read 2 more answers

Stewart (70 Kg) is attracted to Ms. Little (60 Kg) who sits 2 m away. What is the gravitational attraction between them? G=6.67×

ikadub [295]

Happy Holidays!

We can use the following equation to solve for the gravitational force:

$\large\boxed{F_g = G\frac{m_1m_2}{r^2}}$

Fg = force due to gravity (N)

G = Gravitational constant

m1,m2 = masses of the objects (kg)

r = distance between the objects (m)

Plug in the given values into the equation:

$F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}$

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3 years ago

1 mole of air undergoes a Carnot cycle. The hot reservoir is at 800 oC and the cold reservoir is at 25 oC. The pressure ranges b

BabaBlast [244]

Answer:

The net work produced is 30.37 KJ

The efficiency of cycle is 72.3%

Explanation:

For the net work produced, we have the formula:

Work = (Th - Tc)(Sh - Sc)(M)

Where,

Th = higher temperature = 800° C + 273 = 1073 k

Tc = lower temperature = 25° C + 273 = 298 k

Sh = specific entropy at higher temperature

Sc = specific entropy at lower temperature

M = molar mass of air

Using, ideal gas table to find entropy. The table is attached.

therefore,

Work = (1073 k - 298 k)(3.0485235 KJ/kg.k - 1.69528 KJ/kg.k)(0.02896 kg)

Work = (775 k)(1.3532435 KJ/kg.k)(0.02896 kg)

Work = 30.37 KJ

Now, for the efficiency (n), we have a formula:

n = 1 - Tc/Th

n = 1 - (298 k)/(1073 k)

n = 0.723 = 72.3 %

5 0

4 years ago

What can cause a big city to be warmer than the surrounding countryside?

hammer [34]

There are many people in the city and so much traffic that it pollutes the air and makes it warmer where the country dosent have much traffic so there for its cooler

4 0

3 years ago

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