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Valentin [98]
3 years ago
9

An object is five focal lengths from a concave mirror.how do the object and image heights compare?

Physics
1 answer:
enot [183]3 years ago
7 0

An object distance is presented as s = 5f and we know that the mirror equation relates the image distance to the object distance and the focal length.

The mirror equation is 1/f = 1/s + 1/s’ where the variable f stands for the focal length of the mirror. Variable (s) represents the distance between the mirror surface and the object and the variable <span>(s’) represents the distance between the mirror surface and the image. </span>

In addition, a concave mirror will have a positive focal length (f) and a convex mirror will have a negative focal length (f).

Now, we then have 1/f = 1/5f + 1/s’ which is s’ = 5f/4

Then we get the magnification ratio that expresses the size or amount of magnification or reduction of the object or image and to get the magnification, we use this equation: M= s’/s

M= 5f/4x5f

s’ = 1/4s

Therefore, the image height is one fourth of the object height

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Coal is burned and is used to boil water, which in turn produces steam. Now this steam is passed through nozzles. The steam turns a steam turbine. Now the turbine is coupled to a generator. Generator is an electro magnetic device used for conversion of mechanical energy into electrical energy. So in the generator a voltage difference is created and converted into electrical.


Hope this help : )
8 0
3 years ago
Read 2 more answers
A 600-kg car accelerates from rest to 10 m/s^2. What is the force on the car?
iris [78.8K]

Answer:

60000 newtons

Explanation:

Force=mass × acceleration

60000

3 0
3 years ago
Technician A says test lights are great for quick tests on non-computerized circuits. Technician B says you can use a test light
Tpy6a [65]

Answer:

that technician A is right

Explanation:

The test lights are generally small bulbs that are turned on by the voltage and current flowing through the circuit in analog circuits, these two values ​​are high and can light the bulb. In digital circuits the current is very small in the order of milliamps, so there is not enough power to turn on these lights.

From the above it is seen that technician A is right

4 0
4 years ago
Which of the following contributes to the phases of the Moon as seen from Earth?
balandron [24]

Answer: Varying amounts of the Moon's lit surface being visible from Earth.

Explanation:

Phases of the moon can be defined as the different shapes of the moon visible from the Earth. This happens because sun lits up the face of moon and due to different position of moon in the orbit around earth, varying portion of the lit surface of the moon is visible from Earth. Refer to the diagram below:            

4 0
3 years ago
Read 2 more answers
two vehicles have a head on collision. one vehicle has a mass of 3000 kg and moves at 25 m/s while the second vehicle has a mass
emmasim [6.3K]

Answer:

The speed of the combined vehicles is 6.82m/s

Explanation:

Using the law of conservation of momentum which stayed that the sum of momentum of bodies before collision is equal to their sum of momentum after collision. After collision, both object moves with the same velocity.

Momentum = mass×velocity

Before collision:

Momentum of vehicle or mass 3000kg moving with velocity 25m/s

= 3000×25

= 75000kgm/s

Pa = 75000kgm/s

Momentum of vehicle with mass 2500kg moving with velocity of -15m/s

= 2500×-15

= -37500kgm/s

After collision:

Momentum = (3000+2500)V

Where v is their common velocity

Momentum after collision = 5500V

Based on the law:

75000+(-37500) = 5500V

75000-37500 = 5500V

37500 = 5500V

V = 37500/5500

V = 6.82m/s

7 0
3 years ago
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