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Answer:
the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin.
Explanation:
As described in activity 1, the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin. Urea basically is an heavy compound, thus it is at the base of the chain reactions which which major purpose is to break down the amino acids that make up proteins. Albumin on the other hand is a form of protein that simply helps in the transmission of blood and prevent blood from flowing through to other tissue in the body. The liver produces the albumin the body. So going back to the question, the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin.
Answer:6amperes
Explanation:
1/R=1/40 + 1/40
1/R=2/40
Cross multiplying we get
2R=40
Divide both sides by 2
2R/2 =40/2
R=20ohms
Current=voltage ➗ resistance
Current=120 ➗ 20
Current =6amperes
Answer:
Option D 3.9
Explanation:
First, you need to use the correct equation which is the following:
COP = Q/W
Where:
Q = heat absorbed
W = work done by the pump
COP = coefficient of perfomance
We have all the data, so, all you need to do is replace in the above expression and you shoould get the correct result:
COP = 30 / 7.7
COP = 3.896
This result you can round it to 3.9. option D.
Answer:
xf = 5.68 × 10³ m
yf = 8.57 × 10³ m
Explanation:
given data
vi = 290 m/s
θ = 57.0°
t = 36.0 s
solution
firsa we get here origin (0,0) to where the shell is launched
xi = 0 yi = 0
xf = ? yf = ?
vxi = vicosθ vyi = visinθ
ax = 0 ay = −9.8 m/s
now we solve x motion: that is
xf = xi + vxi × t + 0.5 × ax × t² ............1
simplfy it we get
xf = 0 + vicosθ × t + 0
put here value and we get
xf = 0 + (290 m/s) cos(57) (36.0 s)
xf = 5.68 × 10³ m
and
now we solve for y motion: that is
yf = yi + vyi × t + 0.5 × ay × t
² ............2
put here value and we get
yf = 0 + (290 m/s) × sin(57) × (36.0 s) + 0.5 × (−9.8 m/s2) × (36.0 s) ²
yf = 8.57 × 10³ m
