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djyliett [7]
3 years ago
13

What is the term for movement in a particular direction

Physics
1 answer:
stira [4]3 years ago
4 0
Hello User,

The specific term used is velocity. Velocity is the speed of an object in a specific direction.


"Live as if you were to die tomorrow. Learn as if you were to live forever." -Mahatma Gandhi
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Which statements provides evidence that the earth revolves around the sun
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A graduated cylinder contains 17.5 ml of water. When a metal cube is placed onto the cylinder, its water level rises to 20.3 ml.
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V=2.8 ml

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Astronomers currently estimate the age of the universe to be:.
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2 years ago
A car accelerates uniformly from rest to 24.8 m/s in 7.88 s along a level stretch of road. Ignoring friction, determine the aver
nevsk [136]

Answer:

When he weight of the car is 8.55 x 10^{3} N then power = 314.012 KW

When he weight of the car is 1.10 x 10^{4}  N then power =  43.76 KW

Explanation:

Given that

Initial velocity V_{1} = 0

Final velocity V_{2} = 24.8 \frac{m}{s}

Time = 7.88 sec

We know that power required to accelerate the car is given by

P = \frac{change \ in \ kinetic \ energy}{time}

Change in kinetic energy Δ K.E = \frac{1}{2} m (V_{2}^{2} - V_{1}^{2}   )

Since Initial velocity V_{1} = 0

⇒ Δ K.E = \frac{1}{2} m V_{2}  ^{2}

⇒ Power P = \frac{1}{2} \frac{m}{t}  V_{2} ^{2}

⇒ Power P = \frac{1}{2} \frac{W}{g\ t}  V_{2} ^{2}   -------- (1)

(a). The weight of the car is 8.55 x 10^{3} N = 8550 N

Put all the values in above formula

So power P = \frac{1}{2} \frac{8550}{(9.81)\ (7.88)} (24.8) ^{2}

P = 314.012 KW

(b). The weight of the car is 1.10 x 10^{4} N = 11000 N

Put all the values in equation (1) we get

P = \frac{1}{2} \frac{11000}{(9.81)\ (7.88)} (24.8) ^{2}

P = 43.76 KW

5 0
3 years ago
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