To solve this problem we will apply the concepts related to electric potential energy. This relationship shows us that energy is equivalent to half the product between the capacitance of the body by the squared voltage. Mathematically it can be expressed as,
Here,
C = Capacitance
V = Voltage
E = Energy
The initial capacitance would then be given by
Energy stored in the capacitor with 3V is
Therefore the energy stored in the capacitor if it is charged to 3V is 8mJ
Planck find the correct curve for the specturm of light emitted by a hot object by vibrational energies of the atomic resonators were quantized.
<h3>Briefing :</h3>
- The energy density of a black body between λ and λ + dλ is the energy E=hc/λ of a mode times the density of states for photons, times the probability that the mode is occupied.
- This is Planck's renowned equation for a black body's energy density.
- According to this, electromagnetic radiation from heated bodies emits in discrete energy units or quanta, the size of which depends on a fundamental physical constant (Planck's constant). The basis of infrared imaging is the correlation between spectral emissivity, temperature, and radiant energy, which is made possible by Planck's equation.
Learn more about the Planck's constant with the help of the given link:
brainly.com/question/27389304
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