5 N to the right

There’s a force of 6 N pulling to the right (the positive direction) and 1 N pulling left (the negative direction).
Net force= 6 N - 1 N = 5 N to the right

8 0

3 years ago

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Un automovil de 900 kg toma una curva de radio de 40 m con una rapidez constante de 50 km/h. Cual es la fuerza neta necesaria pa

Llana [10]

Answer:

Fc = 4340,93 Newton

Explanation:

Dados los siguientes datos;

Masa = 900 kg

Velocidad, V = 50 km/h a metros por segundo = (50 * 1000)/(60 * 60) = 50000/3600 = 13,89 m/s

Radio, r = 40 m

Para encontrar la fuerza centrípeta;

Fc = mv² / r

Fc = (900 * 13,89²)/40

Fc = (900 * 192,93)/40

Fc = 173637/40

Fc = 4340,93 Newton

4 0

3 years ago

Gasoline burns in the cylinder of an automobile engine. During the combustion reaction, the production of gas forces the piston

serg [7]

Answer:

$\Delta U = 1640 J$

Explanation:

As we know by first law of thermodynamics that for ideal gas system we have

Heat given = change in internal energy + Work done

so here we will have

Heat given to the system = 2.2 kJ

Q = 2200 J

also we know that work done by the system is given as

$W = 560 J$

so we have

$\Delta U = Q - W$

$\Delta U = 2200 - 560$

$\Delta U = 1640 J$

6 0

4 years ago