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defon
3 years ago
12

Technician A says that a flexible coupling may be used to connect the steering shaft to the gear input shaft. Technician B says

that if the coupling breaks the steering will have a loose feel. Which technician is correct?
A) Technician A.
B) Technician B.
C) Technician A and B.
Physics
1 answer:
Hitman42 [59]3 years ago
8 0

Answer:

A

Explanation:

Tech A has all the right components connected together. Tech B thinks that the steering is loose. Think aboout it, would steering be hard or easy if something breaks in tjose components? Definitely hard and clunky!

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Two uniformly charged conducting plates are parallel to each other. They each have area A. Plate #1 has a positive charge Q whil
Marrrta [24]

Answer:5

Explanation:

Given

First Plate has a charge of +Q  and area A

Second Plate has a charge of -3 Q and area A

We Know electric Field due to sheet charge is given by

E=\frac{Q}{2A\epsilon }

Where Q=charge over the Plate

A=Area of plate

\epsilon= Permittivity of free space

Electric Field Due to Positive charge will always be away from it while for negative charge it is towards it.

Net Electric Field at a point between between the Plates is the superimposition of two electric with direction

E_{net}=\frac{Q}{2A\epsilon }+\frac{3Q}{2A\epsilon }

E_{net}=\frac{2Q}{A\epsilon }

Net electric Field is towards the negative charged plate

5 0
4 years ago
A paintball is shot horizontally in the positive x direction at time t after the ball is shot it is 4 cm to the right and 4 cm b
Artist 52 [7]

<u>Answer:</u>

At time 2t the paint ball is at 8 cm to the right and 16 cm to the bottom

<u>Explanation:</u>

 We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Considering the horizontal motion of paint ball

    Distance traveled during time t = 4 cm

    Initial velocity = u m/s

   Acceleration = 0 m/s^2

So 4 = u*t+\frac{1}{2} *0*t^2\\ \\ u = \frac{4}{t}

Now at time 2t,

  S= u*2t+\frac{1}{2} *0*(2t)^2\\ \\=\frac{4}{t} *2t\\ \\ =8cm

  So horizontal distance traveled in time 2t = 8 cm to the right

Now considering the vertical motion of paint ball

  Distance traveled during time t = 4 cm

    Initial velocity = 0 m/s

   Acceleration = -g m/s^2

4=0*t-\frac{1}{2} *g*t^2\\ \\ t^2=\frac{-8}{g}

At time 2t,

     S=0*2t-\frac{1}{2} *g*(2t)^2\\ \\ =-\frac{1}{2} *g*4*\frac{-8}{g}\\ \\ =16 cm

 So vertical distance traveled in time 2t = 16 cm to the bottom

 

6 0
3 years ago
23. Why would an astronomical unit not be<br> used to measure distances on Earth?
Rashid [163]
One Astronomical Unit is the distance between the Earth and the Sun, this acts as a sort of a cosmic metre stick. Astronomers don't and cannot measure distances. Distances are merely inferred from what actually has been measured, such as an angle, a relative luminosity, a time period
3 0
3 years ago
A child pulls on a wagon with a force of 75 N. If the wagon moves a total of 42 m in 3.1 min, what is the average power delivere
exis [7]

Answer:

16.96 W

Explanation:

Power: This can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).

From the question,

P = (F×d)/t....................... Equation 1

Where P = power, F = force, d = distance, t = time.

Given: F = 75 N, d = 42 m, t = 3.1 min = 3.1×60 = 186 s

Substitute these values into equation 1

P = (75×42)/186

P = 16.94 W

Hence the average power delivered by the child  = 16.96 W

4 0
3 years ago
Soil can best be described as the
mr Goodwill [35]
C. It is C because it really is loose covering.
7 0
3 years ago
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