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velikii [3]
3 years ago
7

Which of these quantities is constant in uniform circular motion?

Physics
1 answer:
zvonat [6]3 years ago
3 0
The answer is A, speed
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Please Help No Links
ale4655 [162]

Answer:

the moment of inertia

Explanation:

5 0
3 years ago
Which is true of magnetic field lines but not electric field lines?
marusya05 [52]

D

The closer the field lines, the stronger the field, whereas for electric field, the higher the electric flux passing through, the stronger the electric field.

Explanation:

Another difference between the two is that magnetic fields formed closed loops around the magnetic while electric fields do not. Electric fields are measured in two dimensional while magnetic fields in 3 dimensional. The electric field line can do work while magnetic fields can not (because particles in magnetic field remain constant even though the charge may change direction).

Learn More:

For more on electric and magnetic fields check out;

brainly.com/question/1594186

brainly.com/question/6502405

brainly.com/question/12691714

brainly.com/question/3747739

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#LearnWithBrainly

7 0
4 years ago
Read 2 more answers
A 1500kg car is at rest before it accelerates when the light turns green. If it covers 45.0 meters in 15.0 seconds, what is the
lana [24]

Answer:

300N

Explanation:

Given parameters:

Mass of car  = 1500kg

Initial velocity  = 0m/s

Distance covered  = 45m

Time  = 15s

Unknown:

Net force applied  = ?

Solution:

From Newton's second law:

  Force  = mass x acceleration

  Force  = mass x \frac{v - u}{t}  

v is the final velocity

u is the initial velocity

t is the time taken

    Final velocity  = \frac{45}{15}   =3m/s

 Force  = 1500 x \frac{3 - 0}{15}   = 300N

8 0
3 years ago
A sample of oxygen gas with a volume of 3.0 m3 is at 100 C. The gas is heated so that
vesna_86 [32]

\qquad\qquad\huge\underline{{\sf Answer}}

According to Charles law, if pressure remains constant, volume varies directly with temperature. so we can infer that :

\qquad\sf{\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}

So, we can use this formula to find out the final temperature of the gas ~

Note : Take temperature in Kelvin ( 100°C = 373 K )

\qquad \sf  \dashrightarrow \:  \dfrac{3}{373}  =  \dfrac{6}{x}

\qquad \sf  \dashrightarrow \: x =  \dfrac{6}{3} \times 373

\qquad \sf  \dashrightarrow \: x = 2 \times 373

\qquad \sf  \dashrightarrow \: x =74 6 \: K

Now, convert it to Celsius ~

i.e 746 - 273 = 473° C

So, the final temperature of the gas will be equal to 473° C

6 0
2 years ago
A pilot wants to drop a bomb on a target. His plane is traveling at a speed of 166 m/s horizontallly and is at an altitude of 76
Korvikt [17]

Answer:

2070 m

Explanation:

Find the time to fall from d=  762.5 m to the ground :

   d = 1/2 a t^2     shows t = 12.5 s

Horizontal distance =   166 m/s   * 15.5 s =   2069.7 m =~2070 m

4 0
1 year ago
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