Answer:
104.5 and 109.5
Explanation:
Bond angle is the angle formed between three atoms which has at least two bonds present between them. The number of lone pairs in a covalent bond is a determinant of the bond angle as the lone pairs which are negatively charged repulses the bond pairs thereby creating a distortion and angle.
Studies have however shown that the bond angles in H3O are lesser than 109.5 and greater than 103.5. This provides a bond range of H3O.
<span>Molality(m) or molal concentration is a measure
of concentration and it refers to amount of substance in a specified amount of
mass of the solvent. Used unit for molality is mol/kg which is also
sometimes denoted as 1 molal. It is equal to the moles of solute (the substance
being dissolved) divided by the kilograms of solvent (the substance used to
dissolve).</span>
Molarity(M) or molar concentration is also a
measure of concentration and represents the amount of substance per unit volume
of solution(number of moles per litre of solution. Used unit for molarity is
mol/L or M. A solution with a concentration of 1 mol/L is equivalent to 1 molar
(1 M).
Molality is preferred when
the temperature of the solution varies, because it does not depend on
temperature, (neither number of moles of solute nor mass of solvent will be affected
by changes of temperature), while molarity changes as temperature changes(volume
of solution changes as temperature changes).
Answer:
0.625 moles of CO₂ can be produced by this reaction.
27.5 g of CO₂
Explanation:
A reaction where CO₂ can be produced is combustion.
The reactants are methane (in this case) and oxygen, while the products will be CO₂ and H₂O.
The balanced reaction is: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)
We assume the oxygen is in excess, so the methane gas, is the limiting reagent.
We convert the mass to moles (mass / molar mass) → 10 g / 16 g/mol = 0.625 moles
According to stoichiometry, 1 mol of methane can produce 1 mol of CO₂. Therefore If we have 0.625 moles of CH₄ we produce 0.625 moles of CO₂. Ratio is 1:1.
Let's convert the moles to mass → (mol . molar mass) =
0.625 mol . 44 g/mol = 27.5 g
Answer:
43.5 moles of HNO₃.
Explanation:
The balanced equation for the reaction is given below:
S + 6HNO₃ —> H₂SO₄ + 6NO₂ + 2H₂O
From the balanced equation above,
6 moles of HNO₃ reacted to produce 2 moles of H₂O.
Finally, we shall determine the number of mole of HNO₃ required to produce 14.5 moles of H₂O.
This can be obtained as illustrated below:
From the balanced equation above,
6 moles of HNO₃ reacted to produce 2 moles of H₂O.
Therefore, Xmol of HNO₃ will react to produce 14.5 moles of H₂O i.e
Xmol of HNO₃ = (6 × 14.5)/2
Xmol of HNO₃ = 43.5 moles
Therefore, 43.5 moles of HNO₃ is required to produce 14.5 moles of H₂O.