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3 years ago

13

In a water molecule, shared electons spend more time around th oxygen atom than the hydrogen atoms. as a result, the oxygen atom

is...

1 answer:

Tasya [4]3 years ago

5 0

The oxygen atom has a partial negative charge. Due to the shared electrons spending more time in this region.

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Lipid-soluble hormones usually bind to __________ receptors.

kumpel [21]

Answer:...intercellular receptors

Explanation:

Lipophilic hormone also known as lipid-soluble hormones can pass through the cell's plasma membrane, to bind to intracellular receptors, so as to effect change in gene expression.

3 0

3 years ago

a bar of gold is melted into liquid the liquid is then poured into a mold to make pieces of jewelry is the process a chemical ch

Leviafan [203]

Physical change because it's only changing the shape of the gold.

6 0

3 years ago

The mass percent of solute in a solution containing 3.73 g KBr dissolved in 131 g of H2O is:

Elina [12.6K]

$\huge \underbrace \mathfrak \red{Answer}$

28%

Explanation:

mass of solute(KBr) = 3.73g

mass of solvent(H2O) = 131g

mass of solution = mass of solute + mass of solvent

= 3.73 + 131

= 134.73g

$\sf \large {mass \: percentage = \frac{mass \: of \: solute}{mass \: of \: solvent} \times 100} \\ \\ \sf mass \: percentage = \frac{3.73}{134.73} \times 100 \\ \\ \sf mass \: percentage = 0.028 \times 100 \\ \\ \sf mass \: percentage = 28\%$

7 0

2 years ago

Determine the number of significant figures in 478 cm

Grace [21]

Answer:

There are 3 significant figures on this one.

3 0

2 years ago

The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens

poizon [28]

Answer:

<u>It increases by a factor of four</u>

Explanation:

Boyle's Law : At constant temperature , the volume of fixed mass of a gas is inversely proportional to its pressure.

pV = K.......(1)

pV = constant

Charles law : The volume of the gas is directly proportional to temperature at constant pressure.

V = KT

or V/T = K = constant ....(2)

Applying equation (1) and (2)

$\frac{PV}{T}=K$

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

According to question ,

T2 = 4 (T1)

V2 = V1

Put the value of T2 and V2 , The P2 can be calculated,

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{1}}{4T_{1}}$

V1 and V1 cancel each other

T1 and T1 cancel each other

We get,

$P1=\frac{P2}{4}$

or

P2 = 4 P1

So pressure increased by the factor of four

5 0

3 years ago