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makvit [3.9K]
2 years ago
10

PLEASE HELP ASAP PLEASE​

Mathematics
1 answer:
shutvik [7]2 years ago
3 0

Answer:

-5.5

Step-by-step explanation:

<em>-10, -9, -8, -8,</em> -6, -5, <em>-1, 1, 7, 6</em>

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Which graph represents a function?
vivado [14]

Answer:

c

Step-by-step explanation:

7 0
2 years ago
Solve this equation algebraically!!
NeTakaya

Answer:

See Explanation

Step-by-step explanation:

1 -  \sqrt{x}  \neq \: 0 \\  \\  \therefore \: 1 \neq \sqrt{x}  \\  \\  {1}^{2}  \neq ({ \sqrt{x}) }^{2}  \\  \\ 1 \neq \: x \\

Hence, x will take values other than 1.

5 0
3 years ago
For which value of theta is cot (theta) undefined?
sattari [20]

The cotangent function is defined as the ratio between cosine and sine of a given angle, i.e.


\cot(x) = \frac{\cos(x)}{\sin(x)}


Since you can't have zero at the denominator, the cotangent function is not defined when the sine is zero.


Let's look at your option:


\sin(90^\circ) = 1, so the cotangent is defined here


\sin(180^\circ) = 0, so the cotangent is not defined here


\sin(270^\circ) = -1, so the cotangent is defined here


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6 0
3 years ago
Read 2 more answers
The Johnson twins were born nine years after their older sister. This year, the product of the three siblings ages is exactly 18
KATRIN_1 [288]

Answer: The age of the twins is 10 years.

Step-by-step explanation:

Suppose the age of older sister be x

Let the age of twins sister be x-9, as they are born after 9 years.

Product of their ages be

x(x-9)(x-9)\\\\=x(x^2-18x+81)\\\\=x^3-18x^2+81x

Sum of their ages will be

x+x-9+x-9\\\\=3x-18

According to question,

1861+3x-18=x^3-18x^2+81x\\\\x^3-18x^2+81x-3x+18-1861=0\\\\x^3-18x^2+78x-1843=0\\\\x=19

So, Age of older sister will be 19 years.

Age of the twins will be

19-9=10\ years

Hence, the age of the twins is 10 years.

3 0
3 years ago
A+3 1/4+5 2/9 what is the value of a, explain how you got the answer
larisa86 [58]

Answer:

a+305/36

Step-by-step explanation:

Convert

3

1

4

3

1

4

to an improper fraction.

a

+

13

4

+

5

2

9

a

+

13

4

+

5

2

9

Convert

5

2

9

5

2

9

to an improper fraction.

a

+

13

4

+

47

9

a

+

13

4

+

47

9

To write

13

4

13

4

as a fraction with a common denominator, multiply by

9

9

9

9

.

a

+

13

4

⋅

9

9

+

47

9

a

+

13

4

⋅

9

9

+

47

9

To write

47

9

47

9

as a fraction with a common denominator, multiply by

4

4

4

4

.

a

+

13

4

⋅

9

9

+

47

9

⋅

4

4

a

+

13

4

⋅

9

9

+

47

9

⋅

4

4

Write each expression with a common denominator of

36

36

, by multiplying each by an appropriate factor of

1

1

.

a

+

13

⋅

9

36

+

47

⋅

4

36

a

+

13

⋅

9

36

+

47

⋅

4

36

Combine the numerators over the common denominator.

a

+

13

⋅

9

+

47

⋅

4

36

a

+

13

⋅

9

+

47

⋅

4

36

Simplify the numerator.

a

+

305

36

a

+

305

36

3 0
3 years ago
Read 2 more answers
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