Answer:
Randy had 13 books an Sandy had 7 books.
Step-by-step explanation:
20 - 3 = 17
30 - 17 = 13
13 x 2 = 26
26 + 4 = 30
13 + 7 = 20
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Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
16,00
Step-by-step explanation:
9 years is the (time)
divide the 27 years by 9 to see how many times it doubles
the ans is 3
now simply divide the value which is $4,800 by the 3
this gives you 1,600
It took them 4 days until they arrived at their destination.
314 × 4 = 1256
Another way of solving it:
Total amount of miles ÷ miles per day = The amount of days.
1256 ÷ 314 = 4
