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2 years ago

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Four individuals with high levels of cholesterol went on a special crash diet, avoiding high-cholesterol foods and taking specia

l supplements. Their total cholesterol levels before and after the diet were as follows:Participant Before AfterJ. K. 287 255L. M. M 305 269A. K. 243 245R. O. S. 309 247Using the .05 level of significance, was there a significant change in choles-terol level? (a) Use the steps of hypothesis testing. (b) Sketch the distributions involved. (c) Explain your answer to someone who has never taken a course in statistics.

1 answer:

shutvik [7]2 years ago

3 0

Answer:

uh l.m.a.o this is why im failing math

Step-by-step explanation:

lol

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quadrilateral A'B'C'D' is the image of quadrilateral ABCD after being translated 6 units up and 7 units left. Quadrilateral A pr

Firlakuza [10]

Answer:

$B(x,y) = (-10,-1)$

Step-by-step explanation:

Given

$B' = (-3,5)$

Required

Determine B

When a point is translated up, the result is:

$y'->y + h$

Where h is the unit translated

y' is the new point and y is the previous;

So, we have

$5 = y + 6$

$y = 5 - 6$

$y = -1$

When a point is translated left, the result is:

$x'->x + h$

Where h is the unit translated

x' is the new point and x is the previous;

So, we have

$-3 = x + 7$

$x = -3 - 7$

$x = -10$

Hence, the coordinates of B is

$B(x,y) = (-10,-1)$

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3 years ago

Read 2 more answers

The population of a rabbit colony triples every 3 days. The population starts at 10 rabbits. Write an exponential function that

qaws [65]

Answer:

Step-by-step explanation:

The population at various days is as follows since population triples every 3 days

<u>Day</u> <u>Population</u>

0 10

3 30

6 90

9 270

.... ......

This can be modeled by the general equation

$n_{t} = n_{0}(r)^{t/k}$

where

$n_{t}$ is the population after t days

$n_{0}$ is the population at start (10)

$r$ is the rate at which population changes ie 3

$t$ is the number days from start

$k$ is the number of days at which the population triples(here k =3 days)

We can check this by plugging in values for each of the variables

At day 0, population = 10(3)⁰ = 10. 1 = 10

Similarly populations for days 3, 6, 9 are:

$\\\\10.3^{3/3} = 10. 3^1 = 10.3 = 30\\10.3^{6/3} = 10. 3^2 = 10.9 = 90\\\\10.3^{9/3} = 10. 3^3 = 10.27 = 270$

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1 year ago

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1854times845 could someone help me

vivado [14]

Answer:

1,566,630

Step-by-step explanation:

1854*845=1,566,630

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3 years ago

The parking lot had 1.5 times more trucks than cars. After 45 more cars came to the parking lot and 12 trucks left, there were 1

Anika [276]

11 cars were in the parking lot

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3 years ago

Find cos 0 for 0 = 30° <br><br>The 0 has a weird line through it

Nastasia [14]

Answer: $\frac{\sqrt{3}}{2}$

======================================================

Explanation:

The symbol $\theta$ is the greek letter theta. It's often used in trigonometry for angles.

In this case, $\theta = 30^{\circ}$

So,

$\cos(\theta) = \cos(30^{\circ}) = \frac{\sqrt{3}}{2}$

You'll need to use a reference sheet or the unit circle to determine the value of cos(30). Or you could use a 30-60-90 triangle template.

When using the unit circle, look in the upper right quadrant (which is quadrant 1). The angle 30 degrees is in this quadrant. Locate the terminal point and note how $\frac{\sqrt{3}}{2}$ is the x coordinate of the terminal point. This is due to $x = \cos(\theta)$

Side note: $\frac{\sqrt{3}}{2} \approx 0.866025$

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3 years ago