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3 years ago

What is the best way to classify each equation?

1 answer:

8 0

<span>5x-20=2(3x-10)=6x-20, eqivalent to 5x-20=6x-20, it s a contradicion; a 2. 4x - 16 - 2x = 2(x - 8), for this 4x - 16 - 2x =4x-2x-16=2x-16, and 2(x-8)=2x-16, so 4x - 16 - 2x = 2(x - 8) is a identity 3. For the case of 6x - 15 = 3(2x - 6)=6x-16, we have 6x - 15 = 6x-16 it is contradiction 4. 5x - 3(x - 4) = 2(x - 6), we know that 5x - 3(x - 4) =5x -3x+12=2x+12, and 2(x-6)=2x-12, so we have 2x+12=2x-12. That is also a cotradiction, finally we have 1.B, 2.A, 3.B, 4.B</span>

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natima [27]

Answer:

N is a population parameter; the computation using an estimate of N is a statistic.

Step-by-step explanation:

A parameter is a measure of a population. The number of warplanes fielded total is N; this makes it the population. Thus N is a parameter.

A statistics is a measure of a sample. The number computed using an estimate of N would be based on a sample, since it is an estimate of N; this makes it a statistic.

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3 years ago

What percent of 40 is 5

horsena [70]

Answer:

12.5%

Step-by-step explanation:

Five divided by 40 is 12.5

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3 years ago

Tim goes in a car journey. for the first 15 minutes his average speed is 40mph. he then stops for 25 minutes. he then completes

alisha [4.7K]

15 + 20 equals to 35, 60 - 35 equals to 25 so so his total journey is 1 hour

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2 years ago

Suppose that the trace of a 2×2 matrix a is tr(a)=15 and the determinant is det(a)=50. find the eigenvalues of

IrinaK [193]

Recall that the characteristic polynomial of a 2x2 matrix $\mathbf A=\begin{bmatrix}a&b\\c&d\end{bmatrix}$ is

$\det(\mathbf A-\lambda\mathbf I)=\begin{vmatrix}a-\lambda&b\\c&d-\lambda\end{vmatrix}=(a-\lambda)(d-\lambda)-bc=\lambda^2-(a+d)\lambda+(ad-bc)$

but $\det(\mathbf A)=ad-bc$ and $\mathrm{tr}(\mathbf A)=a+d$ , so the characteristic polynomial for $\mathbf A$ is

$\lambda^2-\mathrm{tr}(\mathbf A)\lambda+\det(\mathbf A)$

We're given that the trace is 15 and determinant is 50, so the characteristic polynomial for the matrix in question is

$\lambda^2-15\lambda+50$

and the eigenvalues are those $\lambda$ for which the characteristic polynomial evaluates to 0.

$\lambda^2-15\lambda+50=(\lambda-5)(\lambda-10)=0\implies\lambda=5,\lambda=10$

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3 years ago

2<br> What is the value of<br> |(6192

Vinvika [58]

Answer:

Face value of digit 6 in 2960543 = 6. Their difference = 60000 - 6 = 59994. 2. Find the product of the place values of two 4s in the numeral 30426451.

Step-by-step explanation:

google

mathonlymath

#if you need any queshtions answered within secs/mins hit me up and I gotchu!

4 0

3 years ago