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Pepsi [2]
4 years ago
7

Use the table of reciprocals to find the reciprocal of these numbers: 0.000 080 25 0.9596

Mathematics
1 answer:
Licemer1 [7]4 years ago
3 0

Answer:

1000000/8025 = 40000/321 (simplified)

1000/9596

Step-by-step explanation:

Hi there,

There is an alternative way to do this....

First it is important to understand what a reciprocal is. The reciprocal of any number x is the number 1/x. The reciprocal of a number is also its multiplicative inverse, which means that the number times its reciprocal must equal 1. For a number such as 2, the reciprocal would be 1/2. For a fraction such as 2/5, the reciprocal would be 5/2.

Finding the reciprocal of a decimal can be done in a number of ways.

Change the decimal to a fraction first.

Ex. 0.25 is 25/100 and is equivalent to the fraction 1/4. Therefore Its reciprocal would be 4/1 or 4.

Keep the decimal and form the fraction 1/?? which can then be or converted to a decimal.

Ex. 0.75 The reciprocal is 1/0.75. Using a calculator, the decimal form can be found by performing the operation: 1 divided by 0.75. The decimal reciprocal in this case is a repeating decimal, 1.33333....

After finding a reciprocal of a number, perform a quick check by multiplying your original number and the reciprocal to determine that the product is 1:

(0.25)(4) = 1.00

(0.75)(1.33....) = 1 but it is easier to see for sure with repeating decimals if you use the fractions instead of the decimals.

(3/4)(4/3) = 12/12 = 1

Hope this helps, Mark as brainliest if liked it! thanks!

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PLEASE HELP ME I NEED HELP ASAP!!!! PLEASE HELP ON A AND B
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Answer:

<h2>a) x = 16 and y = 6</h2><h2>b) P = 864 in</h2>

Step-by-step explanation:

a)

The opposite sides of the rectangle are of equal length.

Therefore we have the system of equations:

\left\{\begin{array}{ccc}3y=2+x&\text{subtract 2 from both sides}\\3x=2+x+5y&\text{subtract x from both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}3y-2=x&(*)\\2x=2+5y&(**)\end{array}\right

Substitute from (*) to (**):

2(3y-2)=2+5y\qquad\text{use distributive property}\\\\(2)(3y)+(2)(-2)=2+5y\\\\6y-4=2+5y\qquad\text{add 4 to both sides}\\\\6y=6+5y\qquad\text{subtract 5y from both sides}\\\\\boxed{y=6}

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PSYCHO15rus [73]
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0.1744 x 145  = 25.29

7 0
3 years ago
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