Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Answer:
16.9 m
Step-by-step explanation:
Start with a half a circle. The central angle of a semicircle is 180 deg.
Now subtract 21 deg on each side.
180 - 21 - 21 = 138
The central angle is 138 deg.
The radius is 7 m.
Now we use the formula for the length of an arc of a circle given the radius of the circle and the central angle of the arc.



Answer:
4.
Step-by-step explanation:
9(2) = 18
18-14=4
The slope for this equation is x=3
I don’t quite understand this question since it’s all spaced out and there’s no picture but since domain is x/the indecent variable, “x = -6, -1, 0, 3” (the first answer choice” is correct