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Alborosie
4 years ago
10

What single transformation maps ∆ABC onto ∆A'B'C'?

Mathematics
2 answers:
masya89 [10]4 years ago
6 0
The answer is B) rotation 90 degrees counterclockwise about the origin
Wittaler [7]4 years ago
4 0

<u>Answer-</u>

<em>The triangle is rotated </em><em>90° counterclockwise</em><em> about the origin.</em>

<u>Solution-</u>

Coordinates of the vertices of the triangle ABC are,

A = (-3, 1)

B = (-1, 2)

C = (-2, 1)

Coordinates of the vertices of the triangle A'B'C' are,

A' = (-1, -3)

B' = (-2, -1)

C' = (-1, -2)

While rotating a point (x, y) 90° counterclockwise, it becomes (-y, x)

i.e (x, y) → (-y, x)

So, the triangle is rotated 90° counterclockwise about the origin.

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\bf f(x) = (x+2)(x-4)\implies 0=(x+2)(x-4)\implies x = \begin{cases} -2\\ 4 \end{cases} \\\\\\ \boxed{-2}\rule[0.35em]{7em}{0.25pt}0\rule[0.35em]{3em}{0.25pt}\stackrel{\downarrow }{1}\rule[0.35em]{10em}{0.25pt}\boxed{4}

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since this is a vertical parabola, its axis of symmetry, the line that splits its into twin sides, will be a vertical line, and it'll be the x-coordinate of the vertex, since the vertex hasa a coordinate of x = 1, then the axis of symmetry is the vertical line of x = 1.

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