Answer:
But there is nothing above
Answer:
Mass of helium = 4426.9524 g
Mass of hydrogen gas = 2213.4762 g
Explanation:
Pressure = 135 atm
Temperature = 24 °C
Volume = 200 L
Number of moles = ?
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (24 + 273.15) K = 297.15 K
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
135 atm × 200 L = n × 0.0821 L.atm/K.mol × 297.15 K
⇒n = 1106.7381 moles
<u>For helium gas:</u>
Molar mass = 4 g/mol
The formula for the calculation of moles is shown below:
Thus,

<u>For hydrogen gas:</u>
Molar mass = 2 g/mol
The formula for the calculation of moles is shown below:
Thus,

This is much more simple than it sounds...
s has 1 orbital; p = 3 orbitals; d= 5 orbitals; f= 7 orbitals. (you just need to memorize this)
A maximum of 2 electrons can occupy each orbital.
<span>The number of orbitals that each atom has is based on the number of electrons it has and by consequence it's position on the periodic table. </span>
The orbitals occur in sequence. Whereby electrons fill first from the lowest energy level (1s) outwards to the highest.
3p = the following sequence.
1s, 2s, 2p, 3s, 3p: these 'sets' can hold the following electrons respectively (2+2+6+2+6) 18 which corresponds with argon on the periodic table. REMEMBER p has 3 orbitals, d has 5 orbitals. So, here there are 9 orbitals.
The sequence through n=4 is:
<span>1s, 2s, 2p, 3s, 3p, 3d, 4s, 4p, 4d, 4f
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer: 0.9375 g
Explanation:
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of
solution = 0.75 M
Volume of
solution = 25.0 mL = 0.025 L
Putting values in equation 1, we get:
According to stoichiometry :
2 moles of
require = 1 mole of
Thus 0.01875 moles of
will require=
of
Mass of
Thus 0.9375 g of
is required to react with 25.0 ml of 0.75 M HCl
Answer:
c a cold air mass and a warm air mass meet with neither moving