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nikdorinn [45]
2 years ago
5

Should industries releasing heavy metals into land and water ecosystem be penalized

Chemistry
1 answer:
sveta [45]2 years ago
7 0

Yes, industries releasing heavy metals into land and water ecosystem be penalized.

Heavy metals are defined as the metals with high density in comparison to water, and presumably, linked with toxicity. The sources of heavy metals other industries include mining activities, waste dumps, untreated sewage etc.

Heavy metals are associated with numerous health issues and thus, are considered dangerous. World Health Organization has set limit on Heavy metals in drinking water. The limits are 3.0 milligram/liter for Zinc, 0.010 milligram/liter for Lead, Arsenic, Mercury and 0.003 milligram/liter for Cadmium.

Heavy metals are associated with disorders concerning gastrointestinal tract, respiratory organs, pulmonary organs, liver and brain. Thus, their discharge into water bodies results in direct or indirect consumption via aquatic food, water absorption by plants etc. The waste from industries should be treated before discharging into land or water bodies. Hence, the industries should definitely be penalized, if releasing heavy metals into land and water ecosystem.

Learn more about industrial waste generation and it's treatment-

brainly.com/question/24593837

brainly.com/question/9841649

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When natural gas is burned, the production of which gas shows that incomplete combustion is occurring?
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Calculate mole fraction of ethylene<br>Glycol in solution<br>containing 20% g C2H6O2 by mass.​
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Answer:

Explanation:

20% of C2H6O2 

since its a solution, this means that it has 20g of ethylene glycol and the rest is water.

Molar mass of C2H6O2 = (12 x 2) + (1 x 6) + (2 x 16)

                                        = 62

mole = mass/molar mass

Moles of C2H6O2 = 20/62

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Moles of water = 80/18

                         = 4.444 mol

mole fraction = mol of solute / tatal mol of solution

Mole fraction of ethylene glycol = 0.322/(0.322 + 4.444)

                                                      = 0.068

Mole fraction of water = 1 - 0.068

                                     = 0.932

7 0
4 years ago
A number of valence electrons can be determined by looking at the... *
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Answer:

The main group number for an element can be found from its column on the periodic table.

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CHEM HELP ASAP!! <br><br> What mass of H2 would be needed to produce 208 kg of methanol?
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So if we use the equation:

CO+2H_{2} → CH_{3}OH

We can then determine the amount of H_{2} needed to produce 208 kg of methanol.

So let's find out how many moles of methanol 208 kg is:

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So then we can solve for moles of methanol:

208kg*\frac{1,000g}{1kg} *\frac{1mol}{32.041g} =6,491.68mol

So now that we have the amount of moles produced, we can use the molar ratio (from the balanced equation) of hydrogen and methanol. This ratio is 2:1 hydrogen:methanol.

Therefore, we can set up a proportion to solve for the moles of hydrogen needed:

\frac{2}{1} =\frac{x}{6,491.68}

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So now that we have the number of moles of H_{2} that are produced, we can then use the molar weight of hydrogen to solve for the mass that is needed:

12,983.36mol*\frac{2.016g}{1mol} =26,174.45g_H_{2}

Therefore, the amount of diatomic hydrogen (H_{2}) that is needed to produce 208kg of methanol is 2.62x10^{4}g.

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