Hugh described two substances which participate in photosynthesis.

Chemistry

2 answers:

Gemiola [76]2 years ago

6 0

B. Substance A is glucose and Substance B is water.

pav-90 [236]2 years ago

3 0

The answer is B because glucose is an energy source and during photosynthesis, water combines with sunlight and carbon dioxide. You can observe by the chemical equation for photosynthesis : 6CO2 + 6H2O + light energy = C6H12O6 + 6O2

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A 1.00 L of a solution is prepared by dissolving 125.6 g of NaF in it. What would be the molarity of this solution?

DedPeter [7]

Answer:

2.99 M

Explanation:

In order to solve this problem we need to keep in mind the definition of molarity:

Molarity = moles of solute / liters of solution

In order to calculate the moles of solute, we convert 125.6 g of NaF into moles using its molar mass:

125.6 g NaF ÷ 42 g/mol = 2.99 mol NaF

As the volume is already given, we can proceed to calculate the molarity:

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denis23 [38]

This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:

First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

$Kb=\frac{[IBH^+][OH^-]}{[IB]}$

Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

$pOH=14-8.20=5.80$

$[OH^-]=10^{-5.8}=1.585x10^{-6}M$

$Kb=10^{-5.20}=6.31x10^{-6}$

Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:

$6.31x10^{-6}=\frac{(1.585x10^{-6})(1.585x10^{-6})}{[IB]}$