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4vir4ik [10]
2 years ago
8

It base please you guys

Chemistry
1 answer:
mihalych1998 [28]2 years ago
3 0

Answer:

Do You Need Help With Anything...??

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Giving brainly if correct​
Kamila [148]

Answer:

D

Explanation:

filtration, the process in which solid particles in a liquid or gaseous fluid are removed by the use of a filter medium that permits the fluid to pass through but retains the solid particles.

Hope that helps

Have a good day

Can I have brain pls

6 0
2 years ago
Read 2 more answers
Does potassium nitrate (KN03) incorporate ionic bonding, covalent bonding, or both? Explain.
ladessa [460]

Answer: KNO_3 incorporates both ionic bonding and covalent bonding.

Explanation:

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here potassium is having an oxidation state of +1 called as K^{+} cation and nitrate NO_3^{-} is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral KNO_3. NO_3^- is formed by sharing of electrons between two non metals nitrogen and oxygen.

Thus KNO_3 incorporates both ionic bonding and covalent bonding.

4 0
3 years ago
Select all of the answers that apply.
shtirl [24]
The odysseyware answer is the same as his wood manure and food crops
5 0
3 years ago
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Which of the following metals will react with water to produce a metal hydroxide and hydrogen gas? (2 points)
vazorg [7]
The answer would be the first option - k
8 0
3 years ago
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Calculate the ph of a solution containing 0.0451 m potassium hydrogen tartrate and 0.028 m dipotassium tartrate. The ka values f
Marina86 [1]

Given buffer:

potassium hydrogen tartrate/dipotassium tartrate (KHC4H4O6/K2C4H4O6 )

[KHC4H4O6] = 0.0451 M

[K2C4H4O6] = 0.028 M

Ka1 = 9.2 *10^-4

Ka2 = 4.31*10^-5

Based on Henderson-Hasselbalch equation;

pH = pKa + log [conjugate base]/[acid]

where pka = -logKa

In this case we will use the ka corresponding to the deprotonation of the second proton i.e. ka2

pH = -log Ka2 + log [K2C4H4O6]/[KHC4H4O6]

     = -log (4.31*10^-5) + log [0.0451]/[0.028]

pH = 4.15



4 0
3 years ago
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