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4 years ago

15

A ball rolls down from the top of a grassy hill, reaches the bottom of the hill, continues to roll, and then starts to slow down

and comes to a stop. What forces caused this ball's motion?

2 answers:

Sladkaya [172]4 years ago

8 0

The answer is gravity

dsp734 years ago

8 0

Gravity caused the ball to roll down from the top of the hill.

Friction with the ground, the grass, and the air, and the energy required
to push grass out of the way, caused it to slow down and come to a stop.

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When gasoline is burned in the cylinder of an engine, it creates a high pressure that pushes the piston. If the pressure is 100.

Marianna [84]

Answer:

$\dot W=2.1074\ hp$

Explanation:

Given:

pressure on the piston, $P=100\ psi=689476\ Pa$

diameter of the piston, $d=3\ in=0.0762\ m$

displacement of the piston, $s=0.05\ m$

time taken in the piston displacement, $t=0.1\ s$

<u>Now, we find the force on the piston:</u>

$F=P.A$

where, A = area upon which pressure acts

$A=\pi.\frac{d^2}{4}$

$A=\pi.\frac{0.0762^2}{4}$

$A=0.00456\ m^2$

$\therefore F=689476\times 0.00456$

$F=3144.2638\ N$

<u>we know that Power is given as:</u>

$\dot W=\frac{F.s}{t}$

$\dot W=\frac{3144.2638\times 0.05}{0.1}$

$\dot W=1572.1319\ W$

$\dot W=2.1074\ hp$

6 0

3 years ago

when a charge of 1 C has an electric PE of 1 J, it has an electric potential of 1 V. When a charge of 2 C has an electric PE of

matrenka [14]

1 volt.
1/1 = 1
2/2 = 1

7 0

3 years ago

The jovian planets (Jupiter, Saturn, Uranus, Netpune) have larger orbits than terrestrial planets (Mercury, Venus, Earth, Mars),

Fofino [41]

Answer:

colder and year

Explanation:

8 0

4 years ago

You are a detective investigating why someone was hit on the head by a falling flowerpot. One piece of evidence is a smartphone

umka21 [38]

Answer:

0.37 m

Explanation:

Given :

Window height, $h_1$ = 1.27 m

The flowerpot falls 0.84 m off the window height, i.e.

$h_2$ = (1.27 x 0.84 ) m in a time span of $t=\frac{8}{30}$ seconds.

Assuming that the speed of the pot just above the window is v then,

$h_2=ut+\frac{1}{2}gt^2$

$(1.27 \times 0.84) = v \times \left( \frac{8}{30} \right) + \frac{1}{2} \times 9.81 \times \left( \frac{8}{30} \right)^2$

$v=\left(\frac{30}{8}\right) \left[ (1.27 \times 0.84) - \left( \frac{1}{2} \times 9.81 \times \left( \frac{8}{30 \right)^2 \right) \right]}$

$v= 2.69$ m/s

Initially the pot was dropped from rest. So, u = 0.

If it has fallen from a height of h above the window then,

$h = \frac{v^2}{2g}$

$h = \frac{(2.69)^2}{2 \times 9.81}$

h = 0.37 m

3 0

3 years ago

How can you make the potential energy as high as possible in a magnetic field between one electromagnet and one piece of iron?

harkovskaia [24]

In step 1, to increase the potential energy, the iron will move towards the electromagnet.

In step 2, to increase the potential energy, the iron will move towards the electromagnet.

<h3>Potential energy of a system of magnetic dipole</h3>

The potential energy of a system of dipole depends on the orientation of the dipole in the magnetic field.

$U = \mu B$

where;

$\mu$ is the dipole moment
B is the magnetic field

$B = \frac{\mu_0 I}{2\pi r}$

$U = \mu\times (\frac{\mu_0 I}{2\pi r} )$

Increase in the distance (r) reduces the potential energy. Thus, we can conclude the following;

In step 1, to increase the potential energy, the iron will move towards the electromagnet.
In step 2, when the iron is rotated 180, it will still maintain the original position, to increase the potential energy, the iron will move towards the electromagnet.

Learn more about potential energy in magnetic field here: brainly.com/question/14383738

7 0

2 years ago