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Valentin [98]
4 years ago
15

A ball rolls down from the top of a grassy hill, reaches the bottom of the hill, continues to roll, and then starts to slow down

and comes to a stop. What forces caused this ball's motion?
Physics
2 answers:
Sladkaya [172]4 years ago
8 0
The answer is gravity
dsp734 years ago
8 0
Gravity caused the ball to roll down from the top of the hill.

Friction with the ground, the grass, and the air, and the energy required
to push grass out of the way, caused it to slow down and come to a stop.
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During combustion reactions, explain why the energy of the reactants must exceed the total energy of the products​
maxonik [38]

Answer:

In these reactions the products are higher in energy than the reactants. ... This barrier is due to the fact that to make CO2 and H2O we have to break 4 carbon-hydrogen bonds and some ...

Explanation:

8 0
3 years ago
Charles' law explains which of these phenomena?
Luden [163]
I think the correct answer would be that Charles' law explains why <span>a balloon deflates when the air around it cools. Charles' law is a simplification of the ideal gas law. At constant pressure,  volume and temperature have a direct relationship. Hope this helps.</span>
5 0
3 years ago
What is the x-component of a vector with a magnitude of 115 km at an angle of 22°?
ruslelena [56]

The x-component of a vector are < 106.6, 43.07 >

Depending on the angle we are provided, the x-component of a vector can either be cos or sin. Cos always corresponds to the right triangle's side that contacts the specified angle.

If a vector v with magnitude ||v|| makes an angle θ with the positive x-axis then,

v = ||v|| cos θi + ||v|| sin θj

 =  < ||v|| cos θ , ||v|| sin θ >

Magnitude p = 115 km

Angle = 22°

p = ||p|| < cos θ, sin θ >

p = 115 < cos 22°, sin 22° >

p = 115 < 0.927, 0.3746 >

p = < 106.6, 43.07 >

Therefore,  the x-component of a vector are < 106.6, 43.07 >

Learn more about vectors here:

brainly.com/question/8043832

#SPJ1

4 0
2 years ago
The acceleration of gravity is -9.8 m/s2. A sling shot fires a rock straight up into the air with a speed of +39.2 m/s. 1. what
Vanyuwa [196]

Given that,

The acceleration of gravity is -9.8 m/s²

Initial velocity, u = 39.2 m/s

Time, t = 2 s

To find,

The final velocity of the shot.

Solution,

Let v is the final velocity of sling shot. Using first equation of motion to find it.

v = u +at

Here, a = -g

v = u-gt

v = (39.2)-(9.8)(2)

v = 19.6 m/s

So, its velocity after 2 seconds is 19.6 m/s.

4 0
3 years ago
The electric field strength is 5.50×10^4 N/C inside a parallel-plate capacitor with a 2.50 mm spacing. A proton is released from
valentina_108 [34]

Answer:

v=1.6\times10^{5}m/s

Explanation:

The equation that relates electric field strength and force that a charge experiments by it is F=qE.

Newton's 2nd Law states F=ma, which for our case will mean:

a=\frac{F}{m}=\frac{qE}{m}

We know from accelerated motion that v^2=v_0^2+2ad

In our case the proton is released from rest, so v_0=0m/s and we get v=\sqrt{2ad}

Substituting, we get our final velocity equation:

v=\sqrt{\frac{2qEd}{m}}

For the <em>proton </em>we know that q=1.6\times10^{-19}C and m=1.67\times10^{-27}kg. Writing in S.I. d=0.0025m, we obtain:

v=\sqrt{\frac{2(1.6\times10^{-19}C)(5.5\times10^{4}N/C)(0.0025m)}{(1.67\times10^{-27}kg)}}=162318.5m/s=1.6\times10^{5}m/s

6 0
3 years ago
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