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Diano4ka-milaya [45]

3 years ago

15

A group of kids is launching water balloons from a hillside with a water balloon slingshot. When the balloons are launched they

start from a height of 31 m above the final position and hit the ground with a final speed of 51 m/s.
Required:
a. Why does the balloon always hit the ground with the same speed regardless of the angle of launch?
b. What is the initial speed of the balloon when it leaves the slingshot?

1 answer:

konstantin123 [22]3 years ago

7 0

Answer:

50

Explanation:

Because he ask to go to the toilet and the teacher said 'i don't know may you?'

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How is refraction and reflection different?

ss7ja [257]

Answer:

Refraction are in parts or are reflected brokely, like light against aluminum. While a reflection, is exact. Like a mirror.

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3 years ago

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A gas is contained in a vertical, frictionless piston-cylinder device. The piston has a mass of mpiston = 2 kg and a cross-secti

BlackZzzverrR [31]

<h2>Answer:</h2>

105146 Pa

<h2>Explanation:</h2>

1) We will make a Free-Body Diagram representing all the upward and downward pressures exerted on the piston.

Downward Pressures:

Pressure exerted by the compressed spring (Pspring)
Pressure due to weight of the piston (Pw)
Atmospheric pressure (Patm)

Upward Pressures:

Initial pressure inside the cylinder. (P1)

2) We will formulate an equation balancing all upward and downward pressures.

P1= Patm + Pw + Pspring

3) We will calculate each of the pressures separately.

Pspring

P = F/A

F= ks

k= 38×1000 =38000 N m

s= 2.5 /1000 = (2.5x10^-3) m

F = 38000×(2.5x10^-3) = 95 N

A = 30/10000 = (30x10^-4) m2

P = 95 / (30x10^-4)

Pspring ≅ 3167 Pa

Pw

P = F/A

F = W = mg

W = 2×9.81 = 19.62 N

A = 30/10000 = (30x10^-4) m2

P = 19.62 / (30x10^-4)

Pw = 654 Pa

Patm

P = 1atm = 101325 Pa

Patm = 101325 Pa

4) We will add all the downward pressures to reach the final answer (initial pressure inside the cylinder).

P1= Patm + Pw + Pspring

P1= 101325+654+3167

P1= 105146 Pa

8 0

3 years ago

A yet-to-be-built spacecraft starts from Earth moving at constant speed to the yet-tobe-discovered planet Retah, which is 20 lig

Gre4nikov [31]

Answer:

The time elapsed at the spacecraft’s frame is less that the time elapsed at earth's frame

Explanation:

From the question we are told that

The distance between earth and Retah is $d = 20 \ light \ hours = 20 * 3600 * c = 72000c \ m$

Here c is the peed of light with value $c = 3.0*10^8 m/s$

The time taken to reach Retah from earth is $t = 25 \ hours = 25 * 3600 =90000 \ sec$

The velocity of the spacecraft is mathematically evaluated as

$v_s = \frac{d }{t}$

substituting values

$v_s = \frac{72000 * 3.0*10^{8} }{90000}$

$v_s = 2.40*10^{8} \ m/s$

The time elapsed in the spacecraft’s frame is mathematically evaluated as

$T = t * \sqrt{ 1 - \frac{v^2}{c^2} }$

substituting value

$T = 90000 * \sqrt{ 1 - \frac{[2.4*10^{8}]^2}{[3.0*10^{8}]^2} }$

$T = 54000 \ s$

=> $T = 15 \ hours$

So The time elapsed at the spacecraft’s frame is less that the time elapsed at earth's frame

7 0

3 years ago

A jet takes off from Florida and flies 100 miles north and then 400 miles west. Determine the total distance travelled by the je

Inessa [10]

Answer:

90m

Explanation:

Distance is not a vector but a scalar quantity. depicted by a quantity only.

hence:

Distance is equal to 30+40+20 = 90 m

5 0

3 years ago

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If a 2kg ball has and initial velocity of

lakkis [162]

Answer:

$\boxed {\boxed {\sf 12 \ Newtons }}$

Explanation:

Force is equal to the product of mass and acceleration.

$F=m*a$

We know the mass, but not the acceleration. Therefore, we must calculate it before we can calculate force.

1. Calculate Acceleration

Acceleration is the change in velocity over the change in time.

$a=\frac{V_f-V_i}{t}$

The final velocity is 10 meters per second and the initial velocity is 4 meters per second. The time is 1 second.

$V_f=10 \ m/s \\V_i= 4 \ m/s \\t= 1 \ s$

Substitute the values into the formula.

$a=\frac{10 \ m/s-4 \ m/s }{1 \ s}$

Solve the numerator.

$a=\frac{6 \ m/s}{1 \ s }$

Divide.

$a= 6 \ m/s/s=6 \ m/s^2$

2. Calculate Force

Now we know the acceleration and the mass.

$m= 2 \ kg \\a= 6 \ m/s^2$

Substitute the values into the fore formula.

$F= 2 \ kg * 6 \ m/s^2$

Multiply.

$F= 12 \ kg*m/s^2$

1 kilogram meter per square second is equal to 1 Newton.
Our answer of 12 kg*m/s² is equal to 12 Newtons

$F= 12 \ N$

The force applies to the ball was <u>12 Newtons.</u>

8 0

3 years ago