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Wittaler [7]
2 years ago
11

Unscramble the bolded letters to guess the 6 letter word code. Did you get the poses or exercises correct? MOUNTAIN POSE TRIANGL

E POSE MOUNTAIN CLIMBERS PLANK TREE POSE JUMPING JACKS PASSWORD Think a type of flexibility ??? Hold that stretch​
Physics
1 answer:
nikitadnepr [17]2 years ago
8 0

Explanation:

I don't see a question...

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Which of the following processes DOES NOT occur during the convective transfer of heat within a container of air? Group of answe
vovangra [49]

The volume of a warmed part of the air is reduced and its density increases.

Explanation:

In a convective form of heat transfer, the volume of a warmed part of air is not reduced and its density does not increase.

During convection, heat causes the warm part of the air to expand and its volume increases. When volume increases, density is reduced.

  • Convection is a form of heat transfer that involves the actual movement of particles of the medium.
  • It usually occurs in fluids i.e gases and liquids.
  • In convection, the cold part exerts a buoyant force on the warmer air below and causes it to rise.
  • As the warmer part is rising the cooler part replaces it and a convective cell is formed in the process.

Learn more:

Energy transfer in the sun brainly.com/question/1140127

#learnwithBrainly

7 0
3 years ago
For which length of wire are the readings of resistance the most precise
levacccp [35]
The resistance of a wire is directly proportional to the length of the wire. That is the longer the length of the wire, the higher the resistance and the shorter the length of the wire, the smaller the resistance.
7 0
2 years ago
What percentage of the takeoff velocity did the plane gain when it reached the midpoint of the runway? a plane accelerates from
ElenaW [278]
When is at the end of the runway the velocity of the plane is given by the equation vf^{2}=0+2*a*s    where s=1800 m is the runway length. Thus
vf^{2}=2*5*1800=18000 (m/s)^{2}      
vf =134.164 (m/s)  

At half runway the velocity of the plane is
v^{2}=2*5* \frac{1800}{2}=9000 ( \frac{m}{s} )^{2}
 
v= \sqrt{9000}=94.87 ( \frac{m}{s})

Therefore at midpoint of runway the percentage of takeoff velocity is
‰P= \frac{v}{vf}=  \frac{94.87}{134.164}=0.707
6 0
3 years ago
Suppose you are sitting on a rotating stool holding a 2 kgmass
Aloiza [94]

Answer:Increase

Explanation:

Given

You are holding 2 kg mass in each outstreched hand

If the masses are dropped then Moment of inertia will decease by 2mr^2

Where m=2 kg

r=length of stretched arm

Since angular momentum is conserved therefore decrease in Moment of inertia will result in increase of angular velocity

as I\omega=constant

I=Moment of inertia

\omega=angular velocity

3 0
3 years ago
What will be the velocity of body in horizontal motion of the body in the air?
satela [25.4K]

Answer: Projectiles travel with a parabolic trajectory due to the influence of gravity. There are no horizontal forces acting upon projectiles and thus no horizontal acceleration, The horizontal velocity of a projectile is constant (a never changing in value.

Explanation: I hoped that helped yall !!

5 0
2 years ago
Read 2 more answers
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