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Wittaler [7]
3 years ago
11

Unscramble the bolded letters to guess the 6 letter word code. Did you get the poses or exercises correct? MOUNTAIN POSE TRIANGL

E POSE MOUNTAIN CLIMBERS PLANK TREE POSE JUMPING JACKS PASSWORD Think a type of flexibility ??? Hold that stretch​
Physics
1 answer:
nikitadnepr [17]3 years ago
8 0

Explanation:

I don't see a question...

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Why do radio waves have the lowest frequency of all the waves on the electromagnetic spectrum?
lara [203]

Explanation:

Electromagnetic waves are the waves which are created as the result of the electrical waves which are perpendicular to each other and also perpendicular to the direction of propagation.

Electromagnetic spectrum is range of the frequencies and their respective wavelengths of the various type of the electromagnetic radiation.

In order of the increasing frequency and the photon energy and the decreasing wavelength the spectrum are:  

radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays and gamma rays.

The energy of the radio waves photons is the lowest of all the other waves in the electromagnetic spectrum.

Also, E={h\times \nu}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

Thus, energy is directly proportional to the frequency. The radio waves have the lowest frequency.

8 0
3 years ago
If you could shine a very powerful flashlight beam toward the Moon, estimate the diameter of the beam when it reaches the Moon.
grin007 [14]

To develop this problem it is necessary to apply the Rayleigh Criterion (Angular resolution)criterion. This conceptos describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major determinant of image resolution.  By definition is defined as:

\theta = 1.22\frac{\lambda}{d}

Where,

\lambda= Wavelength

d = Width of the slit

\theta= Angular resolution

Through the arc length we can find the radius, which would be given according to the length and angle previously described.

The radius of the beam on the moon is

r = l\theta

Relacing \theta

r = l(\frac{1.22\lambda}{d})

r = 1.22\frac{l\lambda}{d}

Replacing with our values we have that,

r = 1.22*(\frac{(384*10^3km)(\frac{1000m}{1km})(550*10^{-9}m)}{7*10^{{-2}}})

r = 3680.91m

Therefore the diameter of the beam on the moon is

d = 2r

d = 2 * (3690.91)

d = 7361.8285m

Hence, the diameter of the beam when it reaches the moon is 7361.82m

8 0
3 years ago
Calculate the Potential Energy of an object that has a mass of 14-kg and is located at a height of 24-m?
inessss [21]
Potential Energy= 24m * 14kg * 9.8N/kg = 3292.8J
4 0
3 years ago
Compared to a stationary galaxy, light from a galaxy that is moving away from earth will appear _____.
Vlad1618 [11]
"B" When an object moves away from us, the light is shifted to the red end of the spectrum, as its wavelengths get longer.
3 0
3 years ago
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A sealed container filled with gas is heated. What happens?
Luda [366]

The internal pressure increases as the gas is heated

5 0
3 years ago
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