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Anna11 [10]
3 years ago
10

6 less than a number is -2 what is the number?

Mathematics
1 answer:
blagie [28]3 years ago
3 0
4 is the number you want
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If 25% of a number is 20, what is 60% of the number
Iteru [2.4K]

Set up a proportion, 20 over 25% and x over 60% and the answer is 48

7 0
3 years ago
Read 2 more answers
Convert 0.827 to a fraction or in simplest form
dangina [55]
<span>0.827 = 0.827 / 1


Numerator = 0.827 × 10 × 10 × 10 = 827
Denominator  = 1 × 10 × 10 × 10 = 1000

Numerator / Denominator = 827 / 1000

Simplifying our fraction

= 827/1000

= 827/1000</span>
7 0
3 years ago
the actual length of wall c is 4 m . to represent wall c noah draw a segment 16cm long what scale is he using explain your reaso
Gnoma [55]

Answer:

1/25

Step-by-step explanation:

1 m = 100 cm

4m x 100 = 400 cm

If it is 16 cm long, then the scale factor is 16/400, which simplifies to 1/25.

7 0
3 years ago
in 2010, the continent of south america has a population of 395,280,204. which of the following is the closest estimate of this
grigory [225]

South America is a subcontinent of the Americas located in the Southern, Western ... with a 2013 population estimated at 386,000,000, according to national estimates of ... By far the most populous country in South America is Brazil, which has ... as high as 8% in the case of Argentina, while unemployment remaining but low

but i would say your answer could be D

6 0
3 years ago
In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th
WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ;   10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, \frac{dx}{dt} = $1,000

Now,

a) computers per household are

since,

mean income of  $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e \frac{dq}{dt}

\frac{dq}{dt} = \frac{d(0.3458 ln x - 3.045)}{dt}

or

\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0

on substituting the values, we get

\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000

or

= 0.01153 computers

6 0
3 years ago
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