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3 years ago

Can someone help me on this

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

4 0

Answer:

m∠A = 91°

Step-by-step explanation:

∠A ≅ ∠B (Vertical Angle Theorem). This means that the two angles will have the same measurements.

Note that a straight line = 180° (Definition of a Straight Line).

Find the value of m∠B.

180 - 47 - 42 = m∠B

m∠B = 180 - (89)

m∠B = 91°

Remember that ∠B & ∠A are vertical angles, so they will have the same measurement.

m∠A = 91°

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Ksivusya [100]

Answer:

x≈13.08

Step-by-step explanation:

We use the pythagora's theorem

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3 years ago

Question 3: Find the vertex of - x2 - 4x + 12

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3 years ago

Samuel is preventing a boulder from rolling down a hill with a slope of 35°. If the boulder

Rashid [163]

Answer:

1,809.98 lb*m/s^2

Step-by-step explanation:

First, we want to know how much weight of the boulder is projected along the path in which the boulder can move.

The weight of the boulder is:

W = 322lb*9.8 m/s^2 = (3,155.6 lb*m/s^2)

This weight has a direction that is vertical, pointing downwards.

Now, we know that the angle of the hill is 35°

The angle that makes the direction of the weight and this angle, is:

(90° - 35°)

(A rough sketch of this situation can be seen in the image below)

Then we need to project the weight over this direction, and that will be given by:

P = W*cos(90° - 35°) = (3,155.6 lb*m/s^2)*cos(55°) = 1,809.98 lb*m/s^2

This is the force that Samuel needs to exert on the boulder if he wants the boulder to not roll down.

3 0

3 years ago

Ms. Carter has 30 boxes of books. Half of the boxes have 25 books and the other half have 50 books. How many books does she have

Nikitich [7]

15 x 25 = 375
15 x 50 = 750

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4 years ago

Read 2 more answers

What is the value of x in the equation (StartFraction one-half EndFractionx + 12) = StartFraction one-half EndFraction(StartFrac

anastassius [24]

Answer:

$x =-24$

Step-by-step explanation:

Given

$(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3$

Required

Solve for x

$(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3$

Open all brackets

$\frac{2}{3}*\frac{1}{2}x + \frac{2}{3}*12 = \frac{1}{2}*\frac{1}{3}x + \frac{1}{2}*14 - 3$

$\frac{2 * 1}{3 *2}x + \frac{2 * 12}{3}= \frac{1 * 1}{2 * 3}x + \frac{1 * 14}{2} - 3$

$\frac{1}{3}x + \frac{24}{3}= \frac{1}{6}x + \frac{14}{2} - 3$

$\frac{1}{3}x +8= \frac{1}{6}x + 7 - 3$

Collect like terms

$\frac{1}{3}x - \frac{1}{6}x =7 - 3 -8$

$\frac{1}{3}x - \frac{1}{6}x =-4$

Solve fraction

$\frac{2-1}{6}x =-4$

$\frac{1}{6}x =-4$

Multiply both sides by 6

$6 * \frac{1}{6}x =-4 * 6$

$x =-4 * 6$

$x =-24$

8 0

3 years ago

Can someone help me on this​

Can someone help me on this