Answer with explanation:
Slope between two points having coordinates,
which lie in a coordinate plane is given by:

1.. Slope of linear function given in table 1, can be calculated by

2. Slope of linear function given in table 2, can be calculated by

3. Slope of linear function given in table 3, can be calculated by

4. Slope of linear function given in table 3, can be calculated by

→Now, slope of line which passes through (0,-3) and (3,3) is

→→→Table 3,
x : -9 -7 -5 -3 -1
y: -25 -21 -17 -13 -9
has same slope as line given equal to 2.