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boyakko [2]
3 years ago
6

Solving inequalities for word problems:

Mathematics
1 answer:
zepelin [54]3 years ago
5 0

For this case we have to:

x: Let the variable representing the unknown number

We algebraically rewrite the given expression:

Twice a number plus 10, is represented as:2x + 10

Three times that number less 4. is represented as:

3x-4

Thus, the complete expression is:

2x + 10> 3x-4

Subtracting 3x from both sides of the inequality:

2x-3x + 10> -4\\-x + 10> -4

Subtracting 10 from both sides of the inequality:

-x> -4-10

Equal signs are added and the same sign is placed:

-x> -14

We multiply by -1 on both sides, taking into account that the sense of inequality changes:

x

The solution is given by all values of "x" less than 14.

Answer:

x

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Answer:

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4 0
4 years ago
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Brrunno [24]
I am assuming that we have to round the numbers to the nearest tens.
When rounding off numbers, if the number is more than half, then you round it up for example, if the number is 15 and you want to round it off, you round it up to 20. But if the number is 14 you round is down to 10

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As for 89, you would round it up to 90 as the 9 in the ones place is more than 5.

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Hope this helps!
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3 years ago
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4 years ago
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luda_lava [24]
                3            
                1
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              x  42
               -------
                1282
              1564
          ----------------
                       
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Hope this helped :)
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