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Feliz [49]
3 years ago
11

The height of a triangle is 8ft greater than the base. The area of the triangle is 136.5 square ft. Find the length of the base

and the height of the triangle
Mathematics
1 answer:
mixer [17]3 years ago
3 0

Answer:

the base is 9/2 ft and the height is 9/2 + 8, or 25/8, ft.

Step-by-step explanation:

Note that the formula for the area of a triangle is A = (1/2)(base)(height).  Let's abbreviate that to A = (1/2)(b)(h).   We are told that h = b + 8.

Then A = 136.5 = (1/2)(b)(b + 8), or

               (after multiplying both sides by 2)

          A = 273 = b^2 + 8b

                which, when put into standard quadratic form, becomes:

b^2 + 8b - 273 = 0

The coefficients of this quadratic are a = 1, b = 8 and c = -273.

Thus, the discriminant is b^2 - 4ac, or 64 - 4(1)(-273) = 1156 = 17^2.

The roots are then

      -8 ± √1156            -8 ± 17

x = --------------------  =  ------------ = 9/2 and -25/2

              2                          2

Only the root 9/2 makes sense here, because measurements of length are positive.

Thus, the base is 9/2 ft and the height is 9/2 + 8, or 25/8, ft.

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A baker buys 19 apples of two different varieties to make pies. The total cost of the apples is $5.10. Granny Smith apples cost
Natasha2012 [34]

The baker bought 7 gala apples, and 12 granny smiths apples

<em><u>Solution:</u></em>

Let "x" be the number of gala apples bought

Let "y" be the number of granny smith apples bought

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Cost of 1 granny smith apple = $ 0.25

<em><u>A baker buys 19 apples of two different varieties to make pies</u></em>

Therefore,

number of gala apples bought + number of granny smith apples bought = 19

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<em><u>The total cost of the apples is $5.10</u></em>

Therefore, we can frame a equation as:

number of gala apples bought x Cost of 1 gala apple + number of granny smith apples bought x Cost of 1 granny smith apple = 5.10

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0.3x + 0.25y = 5.1 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

x = 19 - y ---------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

0.3(19 - y) + 0.25y = 5.1

5.7 - 0.3y + 0.25y = 5.1

5.7 - 0.05y = 5.1

0.05y = 5.7 - 5.1

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<em><u>Substitute y = 12 in eqn 3</u></em>

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