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lora16 [44]
2 years ago
10

What is the remainder of 525 divided by 28?

Mathematics
1 answer:
Travka [436]2 years ago
3 0
The answer is 525 / 28 =18.75 
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If p=1/3 what is 12p
anyanavicka [17]

Step-by-step explanation:

Given

p \:  =  \frac{1}{3}  \\ 12p \:  = 12 \times  \frac{1}{3}  \\  = 4

Hope it will help :)

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2 years ago
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Determine the product (4.2×10^-1)+(5.7+10^-1)
Alenkasestr [34]

Answer: (D) 2.394 * 10^-1

Step-by-step explanation:

(4.2 * 10^-1) (5.7 * 10^-1)

= 2.394 * 10^-1

4 0
3 years ago
a fall dance sold 18 tickets during the first day of sales. this was 25% of the total sales. how many tickets were sold to the f
alexandr402 [8]

Answer:

72

Step-by-step explanation:

I have a weird way of doing it

so if 18 is 25%

18+18=36

then 36 would be 50%

36+36=72

so then 72 would be 100%

72*.25=18

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3 years ago
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A portion of a hiking trail slopes upward at about a 6 angle. To the nearest tenth of a foot, what is the value of x, the distan
kirza4 [7]
The distance covered by the hiker if he traveled a horizontal distance of 120 ft at and angle of 6° will be given by:
cos θ=adjacent/hypotenuse
let the hypotenuse be h, adjacent =120 ft, θ=6°, thus plugging in the values we shall have:
cos 6=120/h
h=120/cos 6
h=120.661 ft
Answer: 120.661 ft
5 0
3 years ago
A report indicated that 37% of adults had received a bogus email intended to steal personal information. Suppose a random sample
fiasKO [112]

Answer:

5.05% probability that no more than 34% had received such an email.

Step-by-step explanation:

We use the binomial approximation to the normal to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 700, p = 0.37

\mu = E(X) = np = 700*0.37 = 259

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{700*0.37*0.63} = 12.77

In a random sample of 700 adults, what is the probability that no more than 34% had received such an email?

34% is 0.34*700 = 238

So this probability is the pvalue of Z when X = 238.

Z = \frac{X - \mu}{\sigma}

Z = \frac{238 - 259}{12.77}

Z = -1.64

Z = -1.64 has a pvalue of 0.0505

5.05% probability that no more than 34% had received such an email.

7 0
3 years ago
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