3. For ΔFHG, find the measure of the smallest angle, ∠HFG, if m∠ GHF = 92° and m∠HGF = 72°
2 answers:
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The area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches is 12.727 square inches
<em><u>Solution:</u></em>
Given that to find area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches
From given information,
Let "c" = hypotenuse = 9 inches
Let "a" = length of one of the leg of triangle = 3 inches
To find: area of triangle
<u><em>The area of triangle when hypotenuse and length of one side of triangle is given:</em></u>
Where, "c" is the length of hypotenuse
"a" is the length of one side of triangle
Substituting the given values we get,
Thus area of triangle is 12.727 square inches
Answer:
1
Step-by-step explanation:
When n -->∞,
90/∞ ---> 0°.
cos(0° )= 1
1^(2n)=1, 1 in any power is 1.